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Dmitriy789 [7]
2 years ago
11

Does the amount of mentos affect the height of the pop explosion

Chemistry
2 answers:
Sergio039 [100]2 years ago
5 0

Answer:

no

Explanation:

bcuz science

Citrus2011 [14]2 years ago
4 0

Answer:

The more mentos you put in a bottle of pop does not necessarily mean a larger explosion. The max amount of mentos with the largest explosion was 4 mentos, it went 350 cm high. With 5 or 6 mentos the explosion went only 330 and 310 cm high.

Hope this helped in some way?

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2 years ago
GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g
JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of H_2 gas and 1 mole of Br_2 liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ

Divide the equation by 2.

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

4 0
3 years ago
Which type of electromagnetic wave has the greatest frequency?(1 point)
Citrus2011 [14]

c. x-rays

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8 0
3 years ago
Whose main job is to break down sugar to release energy that a plant cell can use?
Tasya [4]

Answer:

The Mitochondria

Explanation:

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3 0
3 years ago
How many moles of CH4 are in 148.6 g? Round your answer to two decimal places.
Dafna1 [17]

Answer:

9.29 mol

Explanation:

Given data:

Number of moles = ?

Mass = 148.6 g

Solution:

Number of moles = mass/ molar mass

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Now we will put the values in formula.

Number of moles = 148.6 g/ 16 g/mol

Number of moles = 9.29 mol

Thus 148.6 g have 9.29 moles.

6 0
3 years ago
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