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1 year ago

The average speed of a car on a stretch of interstate is 70 miles per hour. Convert this rate to feet per second.

Mathematics

2 answers:

polet [3.4K]1 year ago

6 0

Answer:

<h3>102. 66 feet / Second</h3>

Step-by-step explanation:

To do conversion change miles into feet and hour into second.

One foot is 5280 feet

And an hour is 3600sec

70 miles / Hour

70 * 5280feet / 3600 second

369600 feet / 3600seconds

Then simplify

102. 66 feet / Second

Diano4ka-milaya [45]1 year ago

4 0

Speed given

70mph

1 mi=5280ft

1h=3600s

So convert

70×5280ft/3600s
7×528ft/36s
102.67ft/s

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F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?

Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) = (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

$l_{HF} = \sqrt{\left (4-7 \right )^{2}+\left (1-(-11) \right )^{2}} = \sqrt{\left (-3 \right )^{2}+\left (12 \right )^{2}} = 3\cdot \sqrt{17}$

Similarly, we check the length of HJ, to get;

$l_{HF} = \sqrt{\left (3-7 \right )^{2}+\left (5-(-11) \right )^{2}} = \sqrt{\left (-4 \right )^{2}+\left (16 \right )^{2}} = 4\cdot \sqrt{17}$

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

7 0

3 years ago

100 pts

lapo4ka [179]

It’s not 100 points it’s only five points

5 0

2 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago

What is the result when 4x3 + 4x² + 13x + 6 is divided by 2x + 1?

Nitella [24]

Answer:

2x^2+x+6

Step-by-step explanation:

if the 4x3 meant 4x^3, then im pretty sure this is the correct answer

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3 years ago

I literally have no clue how to do this.

timurjin [86]

Answer:

Step-by-step explanation:

Sine is opposite divided by the hypotenuse.

sin(30) = 9/y

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y = 18

Cosine is adjacent divided by the hypotenuse

cos(30) = x/18

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3 0

3 years ago