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zheka24 [161]
2 years ago
7

At a certain temperature the reaction

Chemistry
1 answer:
lyudmila [28]2 years ago
5 0

The concentration of carbon monoxide at equilibrium is 0.209 M.

<h3>Concentration of each gas</h3>

CO2 = 2 mol/5 L = 0.4

H2 = 1.5 mol/5L = 0.3

<h3>ICE table</h3>

Create ICE table as shown below

        CO2(g)    +     H2(g) ↔       CO(g)    +     H2O(g)

I          0.4               0.3                0                  0

C        - x                 - x                 x                   x

E        0.4 - x           0.3 - x           x                   x

Kc = [CO][H₂O] / [CO₂][H₂]

2.5 = (x²)/(0.4 - x)(0.3 - x)

x² = 2.5(0.4 - x)(0.3 - x)

x² = 2.5(0.12 - 0.7x + x²)

x²  = 0.3 - 1.75x + 2.5x²

0 = 1.5x² - 1.75x + 0.3

solve the quadratic equation using formula method;

x = 0.209

Thus, the concentration of carbon monoxide at equilibrium is 0.209 M.

Learn more about concentration here: brainly.com/question/17206790

#SPJ1

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The element europium exists in nature as two isotopes: 151eu has a mass of 150.9196 amu, and 153eu has a mass of 152.9209 amu. t
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Two isotopes of europium are 151eu and 153eu

Mass of 151eu = 150.9196 amu

Mass of 153eu = 152.9209 amu

Average atomic mass = 151.96 amu

Let x and y are the relative abundance of two isotopes of europium are 151eu and 153eu

So, x% times 150.9196 + y% times 152.9209 = 151.96

x150.9196 + y152.9209 = 151.96

And x + y = 100% = 1, from here x = 1 – y and y = 1 - x

Solve these equation by substitution,

By replacing x = 1-y, we get

(1-y)150.9196 + y152.9209 = 151.96

150.9196 – 150.9196y + y152.9209 = 151.96

2.0013y = 1.0404

Y =0.5199 = 51.99%

Using the value of y we get,

X = 1-y = 1-51.99 = 0.4801 = 48.01%

<span>So, relative abundance of two isotopes of europium are 151eu and 153eu are 48.01% and 51.99% respectively</span>

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