Answer:
4
Step-by-step explanation:
The reactions are:
Glycolysis: 1 glucose ⟶ 2 pyruvate
Link reaction: 2 × [1 pyruvate ⟶ 1 acetyl CoA]
Citric acid cycle: 2 × [1 AcetylCoA ⟶ 2 CO₂]
Now, add the reactions, cancelling species that occur on both sides of the reaction arrow,
1 glucose ⟶ <u>2 pyruvate
</u>
<u>2 pyruvate</u> ⟶ <u>2 acetyl CoA
</u>
<u>2 AcetylCoA </u>⟶ 4 CO₂
<em>Overall</em> : 1 glucose ⟶ 4 CO₂
For each mole of glucose, four molecules of CO₂ are released in the citric acid cycle.
Answer:
Sodium is higher than Potassium in thesame group
Explanation:
Sodium and potassium are the elements present in the first group of the periodic table. In group, atomic size increases from top to bottom this implies that even atomic radius increases. This causes less attraction force by nucleus on the electrons of outermost orbit of the atom and hence reduces the first ionisation energy, which is the energy required to remove the electron from the outermost orbit of an atom. So, as potassium is below sodium in the group, sodium has greater ionisation energy than potassium
Answer:
the answer to your question is B
Answer:
± 1 or ± 2
Explanation:
Electrovalent bonds are chemical bonds that are established on the premise of transferring electrons between two atoms.
In this bond type, a higly electronegative atom, typically a non-metal receives electrons from an atom with lesser electronegativity, a metal.
To know the number of electrons involved in forming electrovalent bonds, we typically look at the groups of atoms that combines to form the bond.
Metals are found in group I and II on the periodic table. Metals are electropositive and are good electron donors. These metals have 1 and 2 electrons in their valence shell respectively. In like manners, the more electronegative atoms are found in group VI and VII. The elements in these groups are non-metals with high electronegativity and requires just 1 and 2 electrons to complete their octet.
