Average atomic mass of an element is the sum of atomic mass of its isotopes multiplied by their respective percentage abundance.
There are four isotopes of element X:
1. 4.350 % with mass 49.94605 amu
2. 83.79% with mass 51.94051 amu
3. 9.5% with mass 52.94065 amu
4. 2.360% with mass 53.93888 amu
Thus, average atomic mass will be:

Or,

Therefore, average atomic mass of element X will be 51.99 amu (four significant figures)
Answer:
The options are
A.Surroundings get colder and the system decreases in volume.
B.Surroundings get hotter and the system expands in volume.
C.Surroundings get hotter and the system decreases in volume.
D.Surroundings get hotter and the system does not change in volume.
From the Most energy released to the most absorbed , the order is
B. Surroundings get hotter and the system expands in volume.
D. Surroundings get hotter and the system does not change in volume.
C. Surroundings get hotter and the system decreases in volume.
A. Surroundings get colder and the system decreases in volume.
Answer: 1.3% many crosslinks as isoprene units,
Explanation:
Given:
mass pf natural rubber= 200.0g
mass of sulphur = 4.8g
molar mass of sulphur =32g/mol
molar mass of isoprene = C5H8=( 12x5) +(1x8)= 68g/mol
Solution: we first find no of moles present in each using
no of moles = 
Isoprene: 200.0g x [1mole / 68g] = 2.94moles.
Sulfur: 4.8g x [1mole / 32g] x [1 mole crosslinks / 4 moles S] = 0.0375 moles crosslinks.
to find % crosslinked units, we have
0.0375 / 2.94 = 1.3% as many crosslinks as isoprene units,
Answer:
i feel like it would be four
Explanation:
Srr if i was wrong