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3 years ago

Elements that form ionic bonds generally have how many valence electrons? ± 1 or ± 2 ± 2 or ± 3 ± 4 ± 5

Chemistry

1 answer:

11111nata11111 [884]3 years ago

5 0

Answer:

± 1 or ± 2

Explanation:

Electrovalent bonds are chemical bonds that are established on the premise of transferring electrons between two atoms.

In this bond type, a higly electronegative atom, typically a non-metal receives electrons from an atom with lesser electronegativity, a metal.

To know the number of electrons involved in forming electrovalent bonds, we typically look at the groups of atoms that combines to form the bond.

Metals are found in group I and II on the periodic table. Metals are electropositive and are good electron donors. These metals have 1 and 2 electrons in their valence shell respectively. In like manners, the more electronegative atoms are found in group VI and VII. The elements in these groups are non-metals with high electronegativity and requires just 1 and 2 electrons to complete their octet.

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ch4aika [34]

Answer:

4054 kcal of heat is released during complete combustion of 354 g of octane.

Explanation:

Heat of combustion of 1 mol of octane is $1.308\times 10^{3}$ kcal

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We know, no. of moles = (mass)/(molar mass)

So, $1.308\times 10^{3}$ kcal of heat is released during complete combustion of 114.23 g of octane.

So, amount of heat is released during complete combustion of 354 g of octane = $(\frac{1.308\times 10^{3}}{114.23})\times 354$ kcal = 4054 kcal

Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.

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3 years ago

Calculate the standard potential for the following galvanic cell: Fe(s) | Fe2+(aq) || Ag+(aq) | Ag(s) which has the overall bala

Nataly [62]

Answer:

E° = 1.24 V

Explanation:

Let's consider the following galvanic cell: Fe(s) | Fe²⁺(aq) || Ag⁺(aq) | Ag(s)

According to this notation, Fe is in the anode (where oxidation occurs) and Ag is in the cathode (where reduction occurs). The corresponding half-reactions are:

Anode: Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻

Cathode: Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an

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3 years ago

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2 years ago

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3 years ago