1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yuradex [85]
3 years ago
9

Elements that form ionic bonds generally have how many valence electrons? ± 1 or ± 2 ± 2 or ± 3 ± 4 ± 5

Chemistry
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

± 1 or ± 2

Explanation:

Electrovalent bonds are chemical bonds that are established on the premise of transferring electrons between two atoms.

In this bond type, a higly electronegative atom, typically a non-metal receives electrons from an atom with lesser electronegativity, a metal.

To know the number of electrons involved in forming electrovalent bonds, we typically look at the groups of atoms that combines to form the bond.

Metals are found in group I and II on the periodic table. Metals are electropositive and are good electron donors. These metals have 1 and 2 electrons in their valence shell respectively. In like manners, the more electronegative atoms are found in group VI and VII. The elements in these groups are non-metals with high electronegativity and requires just 1 and 2 electrons to complete their octet.

You might be interested in
A scientist is unsure about the accuracy of her experiment. She has checked her equipment and found it to be in good working ord
polet [3.4K]

Answer:

D

Explanation:

The correct thing to do in this case would be to <u>repeat the experiment.</u>

The scientist would need to repeat the experiment in order to double-check the accuracy. If the accuracy is indeed doubtful, he/she can be able to trace the source of the error by repeating the experiment.

The correct option is D.

8 0
2 years ago
Please help I will give brainliest.
iris [78.8K]

Answer:

the second one looks like it so I picked the second one

8 0
3 years ago
1 Na2CO3(aq) + 1 CaCl2(aq) → 1 CaCO3(s) + 2 NaCl(aq) 4. Use the balanced chemical equation from the last question to solve this
LenKa [72]
<h3>Answer:</h3>

0.6 g NaCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] Na₂CO₃ (aq) + CaCl₂ (aq) → CaCO₃ (s) + 2NaCl (aq)

[Given] 0.5 g Na₂CO₃ reacted with excess CaCl₂

<u>Step 2: Identify Conversions</u>

[RxN] Na₂CO₃ → 2NaCl

Molar Mass of Na - 22.99 g/mol

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Na₂CO₃ - 2(22.99) + 12.01 + 3(16.00) = 105.99 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                    \displaystyle 0.5 \ g \ Na_2CO_3(\frac{1 \ mol \ Na_2CO_3}{105.99 \ g \ Na_2CO_3})(\frac{2 \ mol \ NaCl}{1 \ mol \ Na_2CO_3})(\frac{58.44 \ g \ NaCl}{1 \ mol \ NaCl})
  2. Multiply/Divide:                                                                                               \displaystyle 0.551373 \ g \ NaCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

0.551373 g NaCl ≈ 0.6 g NaCl

5 0
2 years ago
Calculate the molarity of 0.850 mol of Na2S in 1.70 L of solution.
Basile [38]

Molarity is simply the ratio of the number of moles of a substance over the total volume of the solution. Assuming that the addition of 0.850 moles does not change the overall volume of 1.70 L, therefore molarity is simply:

 

Molarity = 0.850 moles / 1.70 L = 0.5 moles / L = 0.5 M

5 0
3 years ago
The weights of all elements are always compared to oxygen.
marishachu [46]

Answer:

The weights of all elements are always compared to the Carbon-12.

Explanation:

The weights of all elements are always compared to the Carbon-12 because the mass of carbon is 12 which is the exactly the sum of protons and neutrons.  

Oxygen was also considered the standard for some time but later this stander was rejected because in natural O¹⁷ and O¹⁸ were also present and this create the two different atomic mass tables.

AMU:

Atomic mass unit is define as the 1/12 the mass of an atom of carbon-12.

C12 has six neutron and six protons in the nucleus.

This unit is used to express the masses of atoms. We know that masses of atoms are very small and we do not have any such type of balance that can measure very small quantity. So that is way we use this scale to measure small quantity. For example, according to this scale

relative atomic mass of hydrogen is 1.008 amu

relative atomic mass of oxygen is 15.999 amu

relative atomic mass of uranium is 238.0289 amu

relative atomic mass of chlorine is 35.453 amu

7 0
3 years ago
Other questions:
  • A substance has a density of 6.26 g mL-1. What is the volume that a 2.49 g sample would occupy?​
    10·1 answer
  • What is the charge of a monatomic ion? [A] oxidation number [B] electronegativity [C] polarity [D] negative [E] positive
    8·2 answers
  • What Is a high-temperature physical state of matter in which atoms lose their electrons?
    14·1 answer
  • What is the relationship between accuracy and precision? Please use at least 2 complete content related sentences.
    6·1 answer
  • 39. Which of the following substances are insoluble in water? Select all that apply.
    12·2 answers
  • The following is what kind of reaction?<br> 2 CH4 +4 02 → 2 CO2 + 4H2O
    11·1 answer
  • Balance the folowing equation.<br> S + 02<br> ws<br> SO:
    6·1 answer
  • What should iron oxide be categorized
    10·2 answers
  • What type of bond( ionic or covalent) does silver and nobelium form?
    6·1 answer
  • What provides the energy to set the water cycle in motion?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!