Answer:
Statement A is correct about Sam's box and whisker plot.
Step-by-step explanation:
We have been given a box plot and we are asked to find out true statement according to the box plot.
Since we know data represented by box plot is divided in four equal parts.
Upon looking at our box plot we can see that our data is symmetric. It's median is 15, which means half the math assignments have less than 15 problems and half of the math assignments have more than 15 problems.
Interquartile range represents 50% values of data and it is the difference between upper quartile and lower quartile. IQR is not affected by outliers.
Upon substituting given values from box plot we get,
From IQR we can conclude that half of the assignments contained 15 problems or fewer.Therefore, option A is the correct choice.
-5√x = -15
-5 -5
√x = 3
x = 9
The answer is D.
I don’t even know what to say.
Answer:
Mrs. Habib will have 22.25 feet of border left after she puts border around the board.
Step-by-step explanation:
You must find the perimeter of the board and subtract it from the amount of border she has to find how much she will have left after she uses it. The formula for perimeter is 
, where 
the length of the board, and 
the width of the board. You will add those together and multiply them by 2 because there are 4 sides to a rectangle. That means this equation will look like:
Now you can just solve for the perimeter.
The perimeter is 24 feet. That means it will take 24 feet of border to cover her board. In order to find out how much she'll have left over, just subtract 24 from the total amount of border she has.
Therefore Mrs. Habib will have 22.25 feet of border left over after she covers the bulletin board.
Answer:
The garden is 9 feet wide and 26 feet long.
Step-by-step explanation:
L = W+17
area = LW = 234
(W+17)W = 234
W²+17W-234 = 0
Quadratic formula
W = [-17 ± √(17² – 4·1(-234))] / [2·1]
= [-17 ± √1225] / 2
= [-17 ± 35] /2
= -26, 9
-26 is an extraneous solution
W = 9
L = W+17 = 26
The garden is 9 feet wide and 26 feet long.
