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topjm [15]
2 years ago
13

Determine the ratio of the relativistic kinetic energy to the nonrelativistic kinetic energy (1 2 mÏ2 ) when a particle has a sp

eed of (a) 1.00 Ã 10â3c and (b) 0.970c.
Physics
1 answer:
Gennadij [26K]2 years ago
3 0
Nose kaisisisjbfikfngbr
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A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed th
ValentinkaMS [17]
There are several information's already given in the question. Based on those given information's the answer can be easily deduced. 
First angle of depression = 18°33'
                                        = [18 + (33/60)] degree
                                        = 18.55 degrees
Second angle of depression = 51°33'
                                              = [51 + (33/60)] degrees
                                              = 51.55 degrees
Height of the lighthouse = 200 feet
Then
Distance traveled by the boat from when it
was first noticed until it stopped = (200/tan 18.55) - (200/tan 51.55)
                                                   = (200/0.3356) - (200/1.2594)
                                                   = 594.95 - 158.81
                                                   = 436.14 feet
I hope the procedure is clear enough for you to understand.
7 0
3 years ago
Read 2 more answers
A car accelerates uniformly from rest at 2.2 m / s^2 for 3.0 s.Calculate the speed of the car at time t = 3.0 s
Alexxx [7]

Answer:

6.6m/s

Explanation:

we know that

v = u + at

= 0+ 2.2*3

=6.6m/s

4 0
4 years ago
2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,
Liono4ka [1.6K]

Answer:

The answer is below

Explanation:

The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

h=\frac{u^2sin^2\theta}{2g}

Given that the two projectile has the same height.

For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}

8 0
3 years ago
You need to calculate the volume of berm that has a starting cross-sectional area of 118 SF, and an ending cross-sectional area
LekaFEV [45]
6 cubic feet I’m pretty sure that’s the answer
8 0
3 years ago
Explain the range of effectiveness of each fundamental force by describing the distance that each force influence nearby matter
Bas_tet [7]

Answer:

Actually, gravity is the weakest of the four fundamental forces. Ordered from strongest to weakest, the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity.

6 0
3 years ago
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