Answer:
They don't have equal velocities
Explanation:
We have one bus travelling from Chicago to New York at 30 m/s and one bus travelling from Chicago to San Francisco at 30 m/s.
This is a cheat question. You need to remember that velocity is a vector. Remember that a vector has a direction and a module. So, the answer will be true, if both buses meet both conditions (direction and module). Let's start to analyze:
Module: In this case is 30 m/s for both buses
Direction: In this case is where the buses are heading. One is going to New York, and one is going to San Francisco. So the directions are different.
As module and direction are not the same for both buses we can say that they don't have equal velocities.
Answer:
p to the left
Explanation:
According to law of conservation of momentum "total momentum of an isolated system remains constant".
we consider astronaut and astronaut drill as an isolated system. If the drill gain momentum p to the right so in order for momentum to remain constant the astronaut will gain the same momentum but in opposite direction i.e momentum p to the left.
Initial momentum = 0 ( before she throw astronaut belt)
Final momentum = p - p = 0 (After she throw astronaut belt)
Hence momentum of the system remains constant i.e zero.
Answer:
2.1844 m/s
Explanation:
The principle of conservation of momentum can be applied here.
when two objects interact, the total momentum remains the same provided no external forces are acting.
Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,
assume the bullet goes to right side and the gravitational acceleration =10 
so now the weight of the rifle=
this is a negative velocity to the right side. that means the rifle recoils to the left side
<span>a)
Capacitance = k x ε° x area / separation
ε° = 8.854 10^-12 F/ m
k = 2.4max
average k = 0.78 / 1.27 * 2.4 +(1.27- 0.78) / 1.27 * 1 = 1.474 + 0.386 = 1.86
(61.4 % separation k = 2.4 --- 38.6 % k = 1 air --- average k = 0.614 * 2.34 + 0.386 * 1 = 1.86
area = 145 cm2 = 0.0145 m2
separation = 1.27 cm 0.0127 m
C = 1.86 * 8.854 10^-12 * 0.0145 / 0.0127 = 18.8 pF
b) Q = C * V --- 18.8 * 83 = 1560.4 pC = 1.5604 nC
c) E = V / d = 83 / 0.0127 = 6535.4 V/m </span>
