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REY [17]
3 years ago
13

Explain the range of effectiveness of each fundamental force by describing the distance that each force influence nearby matter

Physics
1 answer:
Bas_tet [7]3 years ago
6 0

Answer:

Actually, gravity is the weakest of the four fundamental forces. Ordered from strongest to weakest, the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity.

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Click the Run Now button to start the simulations. Select "Many rays" and click the Screen checkbox. You should see a lamp and a
Gnoma [55]

Answer:

Answer explained below

Explanation:

(a) The rays are diverging near the lens. They change the direction when they passed through the converging lens

(b) If the light rays don't bend they will move away from the optical (principal axis) as the other waves are moving.

(c) If we decrease the distance between lens and light source, most of the rays diverge and no ray converges on the screen even after passing through the lens. Here is a screenshot.

5 0
3 years ago
A flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic fie
Nutka1998 [239]

Answer:

i = 0.5 A

Explanation:

As we know that magnetic flux is given as

\phi = NBA

here we know that

N = number of turns

B = magnetic field

A = area of the loop

now we know that rate of change in magnetic flux will induce EMF in the coil

so we have

EMF = NA\frac{dB}{dt}

now plug in all values to find induced EMF

EMF = (20)(50 \times 10^{-4})(\frac{6 - 2}{2})

EMF = 0.2 volts

now by ohm's law we have

current = \frac{EMF}{Resistance}

i = \frac{0.2}{0.40} = 0.5 A

5 0
3 years ago
The theoretical line perpindicular to the surface where a light ray hits a mirror is called the
valkas [14]
That's called the "normal" to the surface at that point.
3 0
3 years ago
Given the distance between the crest of one wave and the crest of the next wave, you can determine the?
Sonja [21]
Answer: wavelength !!
hope this helped :)
3 0
3 years ago
g Two masses are involved in a collision on an axis (one dimensional). One mass is six times the mass of the second. Both masses
statuscvo [17]

Answer:

v₁f = 0.5714 m/s   (→)

v₂f = 2.5714 m/s   (→)

e = 1  

It was a perfectly elastic collision.

Explanation:

m₁ = m

m₂ = 6m₁ = 6m

v₁i = 4 m/s

v₂i = 2 m/s

v₁f = ((m₁ – m₂) / (m₁ + m₂)) v₁i +  ((2m₂) / (m₁ + m₂)) v₂i

v₁f = ((m – 6m) / (m + 6m)) * (4) +  ((2*6m) / (m + 6m)) * (2)  

v₁f = 0.5714 m/s   (→)

v₂f = ((2m₁) / (m₁ + m₂)) v₁i +  ((m₂ – m₁) / (m₁ + m₂)) v₂i

v₂f = ((2m) / (m + 6m)) * (4) + ((6m -m) / (m + 6m)) * (2)

v₂f = 2.5714 m/s   (→)

e = - (v₁f - v₂f) / (v₁i - v₂i)   ⇒   e = - (0.5714 - 2.5714) / (4 - 2) = 1  

It was a perfectly elastic collision.

8 0
3 years ago
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