Question

Calculate the number of atoms of bromine in 1.37 g of bromine. Give your answer in scientific notation. Enter your answer in the provided box. x 10 (select)atoms Br

Answer 1

Answer: The number of atoms of bromine present in given number of mass is $1.03\times 10^{22}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of bromine = 1.37 g

Molar mass of bromine = 79.904 g/mol

Putting values in above equation, we get:

$\text{Moles of bromine}=\frac{1.37g}{79.904g/mol}=0.0171mol$

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms.

So, 0.0171 moles of bromine will contain = $0.0171\times 6.022\times 10^{23}=1.03\times 10^{22}$ number of bromine atoms.

Hence, the number of atoms of bromine present in given number of mass is $1.03\times 10^{22}$