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mezya [45]
3 years ago
12

A student was given a solid containing a mixture of nitrate salts. The sample completely dissolved in water, and upon addition o

f dilute HCl, no precipitate formed. The pH was lowered to about 1 and H2S was bubbled through the solution. No precipitate formed. The pH was adjusted to 8 and H2S was again bubbled in. This time, a precipitate formed. Which compounds might have been present in the unknown? The list to choose from: Cr(NO3)3 Co(NO3)2 NaNO3 Ni(NO3)2 Bi(NO3)3 Ca(NO3)2 Sn(NO3)4 Cd(NO3)2
Chemistry
1 answer:
finlep [7]3 years ago
5 0

Answer:

Explanation:

   The nitrates of Bi,Sn and Cd is ruled out because their sulfides are insoluble in acidic medium.

Nitrates of Ni or Co may be present because their sulfides are insoluble in basic medium. The presence of other nitrates are ruled out.

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Which method most effectively measures the volume of an irregularly shaped object?
BigorU [14]

Answer:

It seems maybe A is correct answer

3 0
3 years ago
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HURRY PLEASE! True or false: Making an observation is the first step of the scientific method.
lions [1.4K]

Answer:

True

Explanation:

You must first observe your data then form a hypothesis.

8 0
4 years ago
Find the cell potential for a system whose ∆G = +55 kJ and 3 moles of electrons are exchanged.
rosijanka [135]

Answer:- cell potential = -0.19 volts

Solution:- The equation that shows the connection between \Delta G and cell potential, E is written  as:

\Delta G=-nFE

in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is \frac{96485C}{mol} .

It asks to calculate the value of E, so let's rearrange the equation:

E=-\frac{\Delta G}{nF}

Let's plug in the values in it:

E=-\frac{55kJ}{3mol*96485C.mol^-}

E=-\frac{0.00019kJ}{C}

since, \frac{1kJ}{C}=1000V

Where C stands for coulombs and V stands for volts.

So, E=-\frac{0.00019kJ}{C}(\frac{1000V}{\frac{1kJ}{C}})

E = -0.19 V

So, the cell potential is -0.19 volts.


4 0
3 years ago
The iupac name for ch3–ch2–c ≡ c–ch3 is ________
NNADVOKAT [17]
The IUPAC name of the compound <span>ch3–ch2–c ≡ c–ch3 is PEN-2-YNE or 2-PENTYNE.

Attached below is a diagram that fully explains how the name was given and derived.</span>

7 0
4 years ago
Given the following balanced chemical equation:
Fudgin [204]

Answer:

Mass of Ca(OH)₂ required  = 0.09 g  

Explanation:

Given data:

Volume of HNO₃ = 25 mL (25/1000 = 0.025 L)

Molarity of HNO₃ = 0.100 M

Mass of Ca(OH)₂ required  =  ?

Solution:

Chemical equation;

Ca(OH)₂ + 2HNO₃   →      Ca(NO)₃ + 2H₂O

Number of moles of HNO₃:

Molarity = number of moles / volume in L

0.100 M = number of moles / 0.025 L

Number of moles = 0.100 M ×0.025 L

Number of moles = 0.0025 mol

Now we will compare the moles of Ca(OH)₂  with HNO₃ from balance chemical equation.

                   HNO₃           :           Ca(OH)₂    

                       2               :              1

                  0.0025         :            1/2×0.0025 = 0.00125

Mass of Ca(OH)₂:    

Mass = number of moles × molar mass

Mass =   0.00125 mol × 74.1 g/mol

Mass = 0.09 g    

7 0
4 years ago
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