Answer:
It seems maybe A is correct answer
Answer:
True
Explanation:
You must first observe your data then form a hypothesis.
Answer:- cell potential = -0.19 volts
Solution:- The equation that shows the connection between
and cell potential, E is written as:

in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is
.
It asks to calculate the value of E, so let's rearrange the equation:

Let's plug in the values in it:


since, 
Where C stands for coulombs and V stands for volts.
So, 
E = -0.19 V
So, the cell potential is -0.19 volts.
The IUPAC name of the compound <span>ch3–ch2–c ≡ c–ch3 is
PEN-2-YNE or
2-PENTYNE.
Attached below is a diagram that fully explains how the name was given and derived.</span>
Answer:
Mass of Ca(OH)₂ required = 0.09 g
Explanation:
Given data:
Volume of HNO₃ = 25 mL (25/1000 = 0.025 L)
Molarity of HNO₃ = 0.100 M
Mass of Ca(OH)₂ required = ?
Solution:
Chemical equation;
Ca(OH)₂ + 2HNO₃ → Ca(NO)₃ + 2H₂O
Number of moles of HNO₃:
Molarity = number of moles / volume in L
0.100 M = number of moles / 0.025 L
Number of moles = 0.100 M ×0.025 L
Number of moles = 0.0025 mol
Now we will compare the moles of Ca(OH)₂ with HNO₃ from balance chemical equation.
HNO₃ : Ca(OH)₂
2 : 1
0.0025 : 1/2×0.0025 = 0.00125
Mass of Ca(OH)₂:
Mass = number of moles × molar mass
Mass = 0.00125 mol × 74.1 g/mol
Mass = 0.09 g