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mezya [45]
2 years ago
12

A student was given a solid containing a mixture of nitrate salts. The sample completely dissolved in water, and upon addition o

f dilute HCl, no precipitate formed. The pH was lowered to about 1 and H2S was bubbled through the solution. No precipitate formed. The pH was adjusted to 8 and H2S was again bubbled in. This time, a precipitate formed. Which compounds might have been present in the unknown? The list to choose from: Cr(NO3)3 Co(NO3)2 NaNO3 Ni(NO3)2 Bi(NO3)3 Ca(NO3)2 Sn(NO3)4 Cd(NO3)2
Chemistry
1 answer:
finlep [7]2 years ago
5 0

Answer:

Explanation:

   The nitrates of Bi,Sn and Cd is ruled out because their sulfides are insoluble in acidic medium.

Nitrates of Ni or Co may be present because their sulfides are insoluble in basic medium. The presence of other nitrates are ruled out.

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The answer should be D, cells can only create an identical copy of the original cell.
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3 years ago
Potassium iodide reacts with lead(II) nitrate in this precipitation reaction: 2 KI(aq) + Pb(NO3)2(aq) → 2 KNO3(aq) + PbI2(s) Wha
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Answer:

a. 174 mL

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Let's consider the following reaction.

2 KI(aq) + Pb(NO₃)₂(aq) → 2 KNO₃(aq) + PbI₂(s)

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0.1550 L × 0.112 mol/L = 0.0174 mol

The molar ratio of KI to Pb(NO₃)₂ is 2:1. The moles of KI are:

2 × 0.0174 mol = 0.0348 mol

The volume of a 0.200 M KI solution that contains 0.0348 moles is:

0.0348 mol × (1 L / 0.200 mol) = 0.174 L = 174 mL

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8 0
1 year ago
1.20×10−8s to nanoseconds
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