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mezya [45]
2 years ago
12

A student was given a solid containing a mixture of nitrate salts. The sample completely dissolved in water, and upon addition o

f dilute HCl, no precipitate formed. The pH was lowered to about 1 and H2S was bubbled through the solution. No precipitate formed. The pH was adjusted to 8 and H2S was again bubbled in. This time, a precipitate formed. Which compounds might have been present in the unknown? The list to choose from: Cr(NO3)3 Co(NO3)2 NaNO3 Ni(NO3)2 Bi(NO3)3 Ca(NO3)2 Sn(NO3)4 Cd(NO3)2
Chemistry
1 answer:
finlep [7]2 years ago
5 0

Answer:

Explanation:

   The nitrates of Bi,Sn and Cd is ruled out because their sulfides are insoluble in acidic medium.

Nitrates of Ni or Co may be present because their sulfides are insoluble in basic medium. The presence of other nitrates are ruled out.

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Dahasolnce [82]

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the cell enentually dies because it has no way to survive

Explanation:

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Please help I tired of doing this
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Answer:

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What is this element 1s22s22p6?
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6 0
3 years ago
Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³,what is the thickness of a piece of tin f
leonid [27]

Answer:

15.0 µm

Step-by-step explanation:

Density = mass/volume

        D = m/V     Multiply each side by V

      DV = m        Divide each side by D

        V = m/D

Data:

m = 1.091 g

D = 7.28 g/cm³

 l = 10.0 cm

w = 10.0 cm

Calculation:

<em>(a) Volume of foil </em>

V = 1.091 g  × (1 cm³/7.28 g)

  = 0.1499 cm³

(b) <em>Thickness of foil </em>

The foil is a rectangular solid.

V  = lwh                            Divide each side by lw

h = V/(lw)

   = 0.1499/(10 × 10)

   = 1.50 × 10⁻³ cm           Convert to millimetres

   = 0.015 mm                  Convert to micrometres

   = 15.0 µm

The foil is 15.0 µm thick.

4 0
2 years ago
Alveoli are tiny sacs of air in the lungs. Their average diameter is 4.50 × 10−5 m. Calculate the uncertainty in the velocity of
Arisa [49]

<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

<u>Explanation:</u>

The diameter of the molecule will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

\Delta x.\Delta p=\frac{h}{2\pi}

where,

\Delta x = uncertainty in position = d = 4.50\times 10^{-5}m

\Delta p = uncertainty in momentum  = m\Delta v

m = mass of oxygen molecule = 5.30\times 10^{-26}kg

h = Planck's constant = 6.627\times 10^{-34}kgm^2/s^2

Putting values in above equation, we get:

4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s

Hence, the uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

8 0
3 years ago
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