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mezya [45]
3 years ago
12

A student was given a solid containing a mixture of nitrate salts. The sample completely dissolved in water, and upon addition o

f dilute HCl, no precipitate formed. The pH was lowered to about 1 and H2S was bubbled through the solution. No precipitate formed. The pH was adjusted to 8 and H2S was again bubbled in. This time, a precipitate formed. Which compounds might have been present in the unknown? The list to choose from: Cr(NO3)3 Co(NO3)2 NaNO3 Ni(NO3)2 Bi(NO3)3 Ca(NO3)2 Sn(NO3)4 Cd(NO3)2
Chemistry
1 answer:
finlep [7]3 years ago
5 0

Answer:

Explanation:

   The nitrates of Bi,Sn and Cd is ruled out because their sulfides are insoluble in acidic medium.

Nitrates of Ni or Co may be present because their sulfides are insoluble in basic medium. The presence of other nitrates are ruled out.

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prohojiy [21]

Explanation:  

Z = atomic mass of the element and  , A = atomic mass of the element .

a) Z = 11, A =  23

Element = Sodium

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b) Z = 28, A =  64

Element = Nickel

  symbol: ⁶⁴₂₈Ni  .

c) Z = 50, A = 115

Element = tin

  symbol: ¹¹⁵₅₀Sn  .

d) Z = 20, A = 42

Element = Calcium

  symbol: ⁴²₂₀Ca .

6 0
3 years ago
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Answer:

0.159 M

Explanation:

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\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M

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