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Sloan [31]
3 years ago
15

a dog is trained to sit and shake hands. These traits are most likely? a. inherited b. not inherited c. not acquired d. innate

Chemistry
1 answer:
Ksenya-84 [330]3 years ago
4 0
<span>A dog is trained to sit and shake hands. These traits are most likely?

Answer: B not </span>acquired 

hope this helps
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Explain why a spinning top will not remain in motion forever
AlexFokin [52]
Friction of the air, and the surface it is on
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Two characteristics used to classify igneous rocks are texture and
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<span>Two characteristics used to classify igneous rocks are texture and </span>Mineral Grains

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1. A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C. If the
Maurinko [17]

Answer:

Mass of aluminium in sample = 3.591 g ≅ 3.6 grams

Explanation:

Given that,  A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C.

the specific heat of aluminum is 0.900 J/g- °C

The relation between heat absorbed and change in temperature is given by,   Q = msΔT.

where Q = heat absorbed

            m = mass of the substance

            s = specific heat of substance

          ΔT  = change in temperature

Now, in our case, Q = 50.1 J ; s = 0.900 J/g- °C; ΔT= 35.5-20 = 15.5°C

⇒ m =  \frac{Q}{s(T_{2} -T_{1}) }

⇒ m = \frac{50.1}{0.900(15.5)} = 3.591 g ≅ 3.6 g

⇒ m ≅ 3.6 g

5 0
3 years ago
he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
wolverine [178]

1) Drift velocity: 3.32\cdot 10^{-4}m/s

2) 5.6\cdot 10^{13} electrons per person

Explanation:

1)

For a current flowing through a conductor, the drift velocity of the electrons is given by the equation:

v_d=\frac{I}{neA}

where

I is the current

n is the concentration of free electrons

e=1.6\cdot 10^{-19}C is the electron charge

A is the cross-sectional area of the wire

The cross-sectional area can be written as

A=\pi r^2

where r is the radius of the wire. So the equation becomes

v_d=\frac{I}{ne\pi r^2}

In this problem, we have:

I = 8.0 A is the current

8.5\cdot 10^{28} m^{-3} is the concentration of free electrons

d = 1.5 mm is the diameter, so the radius is

r = 1.5/2 = 0.75 mm = 0.75\cdot 10^{-3}m

Therefore, the drift velocity is:

v_d=\frac{8.0}{(8.5\cdot 10^{28})(1.6\cdot 10^{-19})\pi(0.75\cdot 10^{-3})^2}=3.32\cdot 10^{-4}m/s

2)

The total length of the cord in this problem is

L = 3.00 m

While the cross-sectional area is

A=\pi r^2=\pi (0.75\cdot 10^{-3})^2=1.77\cdot 10^{-6} m^2

Therefore, the volume of the cord is

V=AL (1)

The number of electrons per unit volume is n, so the total number of electrons in this cord is

N=nV=nAL=(8.5\cdot 10^{28})(1.77\cdot 10^{-6})(3.0)=4.5\cdot 10^{23}

In total, the Earth population consists of 8 billion people, which is

N'=8\cdot 10^9

Therefore, the number of electrons that each person would get is:

N_e = \frac{N}{N'}=\frac{4.5\cdot 10^{23}}{8\cdot 10^9}=5.6\cdot 10^{13}

7 0
3 years ago
Classify a solution with a ph of 13
omeli [17]
Well it's definitely an alkaline solution. 
6 0
3 years ago
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