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stira [4]
3 years ago
14

In two or more complete sentences describe all of the van der Waals forces that exist between molecules of sulfur

Chemistry
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer:

The correct answer is "there are many Van der Waals forces acting between molecules of sulfur dioxide"

Explanation:

Van Der Waals forces are considered one of the weakest forces, however, since they exist in multiple levels, they have a major influence in molecules behavior. Van Der Waals forces are intermolecular interactions that emerge from the electrons movement in the atoms and the place that the electrons have in a given moment. In the case of sulfur dioxide, the atoms of sulfur and oxygen have Van Der Waals forces within them and among them. Particularly, the electrons within the individual atoms, as well as the electrons able to interact among the sulfur dioxide molecules, have all Van Der Waals forces.

zavuch27 [327]3 years ago
3 0

Answer:

Dipole-Dipole attraction

Explanation:

Dipole-dipole attraction is a type of vander waals forces found in the molecules of sulfur dioxide.

Vander waals forces are weak attractions joining non-polar and polar molecules together. They are of two types:

  • London dispersion forces which are weak attractions found between non-polar molecules.
  • Dipole-Dipole attraction are the forces of attraction which exists between polar molecules. Such molecules have permanent dipoles. This implies that the positive pole of one molecule attracts the negative pole of another. This is what happens between the oxygen and sulfur molecules.
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When the pressure that a gas exerts on a sealed container changes from 1100 bar to 75.5 bar, the temperature changes from k to 2
Serjik [45]
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
\frac{P1}{T1} =  \frac{P2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{1100 bar}{T}  =  \frac{75.5 bar}{298 K}
T = 4342 K
initial temperature was 4342 K
7 0
3 years ago
Which one of these are correct?
Sergio [31]

The correct answer is the one in the middle. Mixing food coloring and water

3 0
2 years ago
The common pathway for the oxidation of glucose and fatty acids is ________.
finlep [7]
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3 0
3 years ago
The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-
grin007 [14]

Answer:

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

2N_2O \rightarrow 2N_2 + O_2

rate constant k =  1.94\times 10^{-4} min^{-1}

Half life t_{1/2} = \frac{0.693}{k} = 3572 min

Initial pressure N_2 O = 4.70 atm

Pressure after 3572 min = P

According to first order kinematics

k = \frac{1}{t} ln\frac{4.70}{P}

1.94\times 10^{-4} = \frac{1}{3572} \frac{4.70}{P}

solving for P we get

P = 2.35 atm

2N_2O \rightarrow 2N_2 + O_2

initial           4.70                         0             0

change        -2x                          +2x           +x

final             4.70 -2x                     2x           x

pressure ofO_2 after first half life  = 2.35 = 4.70 - 2x

                                                          x = 1.175

pressure of N_2 after first half life  =  2x = 2(1.175) = 2.35 ATM

Total pressure  = 2.35 + 2.35 + 1.175

                          = 5.875 atm

5 0
3 years ago
Read 2 more answers
`Let's just consider the concept of stoichiometry without any confusing chemicals. Here is a generic equation: 2A + 6B ? 3C. If
lesya [120]

Answer:

Option D. 5.5

Explanation:

The equation is this:

2A + 6B  ⇒  3C

With the amounts that we were given, let's determine which is the <em>limting reactant</em>

2 A reacts with 6 B

4 A will react with ( 4 .6)/2 = 12B

I have 11 B, so the limiting is B

6 B react with 2 A

11 B will react with (11 .2 )/6 =3.66 A

I have 4 A, so A is the excess.

6 B produce 3 C

11 B will produce ( 11 .3)/6 = 5.5C

7 0
3 years ago
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