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stira [4]
3 years ago
14

In two or more complete sentences describe all of the van der Waals forces that exist between molecules of sulfur

Chemistry
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer:

The correct answer is "there are many Van der Waals forces acting between molecules of sulfur dioxide"

Explanation:

Van Der Waals forces are considered one of the weakest forces, however, since they exist in multiple levels, they have a major influence in molecules behavior. Van Der Waals forces are intermolecular interactions that emerge from the electrons movement in the atoms and the place that the electrons have in a given moment. In the case of sulfur dioxide, the atoms of sulfur and oxygen have Van Der Waals forces within them and among them. Particularly, the electrons within the individual atoms, as well as the electrons able to interact among the sulfur dioxide molecules, have all Van Der Waals forces.

zavuch27 [327]3 years ago
3 0

Answer:

Dipole-Dipole attraction

Explanation:

Dipole-dipole attraction is a type of vander waals forces found in the molecules of sulfur dioxide.

Vander waals forces are weak attractions joining non-polar and polar molecules together. They are of two types:

  • London dispersion forces which are weak attractions found between non-polar molecules.
  • Dipole-Dipole attraction are the forces of attraction which exists between polar molecules. Such molecules have permanent dipoles. This implies that the positive pole of one molecule attracts the negative pole of another. This is what happens between the oxygen and sulfur molecules.
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A flexible container at an initial volume of 3.10 L contains 9.51 mol of gas. More gas is then added to the container until it r
Schach [20]

Answer:

49.09 moles of gas are added to the container

Explanation:

Step 1: Data given

Initial volume = 3.10 L

Number of moles gas = 9.51 moles

The final volume = 19.1 L

The pressure, temperature remain constant

Step 2: Calculate number of moles gas

V1/n1 = V2/n2

⇒with V1 = the initial volume of the gas = 3.10 L

⇒with n1 = the initial number of moles = 9.51 moles

⇒with V2 = the increased volume = 19.1 L

⇒with n2 = the final number of moles gas

3.10L / 9.51 moles = 19.1 L / n2

n2 = 58.6 moles

The new number of moles is 58.6

Step 3: calculate the number of moles gas added

Δn = 58.6 - 9.51 = 49.09 moles

49.09 moles of gas are added to the container

7 0
3 years ago
Which of the following have deliquescent Nature ? ​
Alla [95]

Answer:

Most deliquescent substances are salts. Examples include sodium hydroxide , potassium, hydroxide, ammonium chloride, gold

4 0
3 years ago
Please help! 50 points and Brainliest!
olga2289 [7]

Answer:

exothermic reaction

Explanation:  

I think this because this is an example of an exothermic reaction is the chemical reaction between sodium and chlorine, which results in the formation of sodium chloride (also known as common salt)

8 0
2 years ago
Read 2 more answers
You need 270 ml of a 65% alcohol solution. on hand, you have a 90% alcohol mixture. how much of the 90% alcohol mixture and pure
olganol [36]

You must add 75 mL water to 195 mL 90 % alcohol to make 270 mL of 65 % alcohol.

<em>Step 1.</em> Calculate the volume of 90 % alcohol needed

You can use the dilution formula

<em>V</em>1×<em>C</em>1 = <em>V</em>2×<em>C</em>2

where

<em>V</em>1 and<em> V</em>2 are the volumes of the two solutions

<em>C</em>1 and <em>C</em>2 are the concentrations

You can solve the above formula to get

<em>V</em>2 = <em>V</em>1 × <em>C</em>1/<em>C</em>2

<em>V</em>1 = 270 mL; <em>C</em>1 = 65 %

V2 = ?; _____<em>C</em>2 = 90 %

∴<em>V</em>2 = 270 mL × (65 %/90 %) = 195 mL

You need 195 mL of 90 % alcohol to make 270 mL of 65 % RA

<em>Step 2</em>. Calculate the amount of water to add.

Volume of water = 270 mL – 195 mL = 75 mL

8 0
3 years ago
6. A balloon filled with air has a volume of 3.25 L at 30°C. It is placed in a freezer at
Viefleur [7K]

Answer:

2.82 L

T₁ = 303 K

T₂ = 263 K

The final volume is smaller.

Explanation:

Step 1: Given data

  • Initial temperature (T₁): 30 °C
  • Initial volume (V₁): 3.25 L
  • Final temperature (T₂): -10 °C
  • Final volume (V₂): ?

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

T₁: K = 30°C + 273.15 = 303 K

T₂: K = -10°C + 273.15 = 263 K

Step 3: Calculate the final volume of the balloon

Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 3.25 L × 263 K/303 K = 2.82 L

7 0
2 years ago
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