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Molodets [167]
3 years ago
9

Concentrations-

Chemistry
1 answer:
Arisa [49]3 years ago
6 0
Moles of HCl is 3.47mol

Work shown on photo

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Vanillin (used to flavour vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest
Rudiy27

Answer:

The cost is $0.063.

Explanation:

First, we need to express the volume of the hangar in liters. We know that 1 ft³ = 28.31 L, so using proportions:

5.0 \times 10^{7} ft^{3} .\frac{28.31L}{1ft^{3} } =1.4 \times 10^{9} L

The amount of vanillin required would be:

1.4 \times 10^{9} L.\frac{2.0\times 10^{-11}g }{1L} =0.028g

Finally, the price for such amount of vanillin is:

0.028g.\frac{ \textdollar 112}{50g}=  \textdollar 0.063

6 0
2 years ago
Which statement is true about HCI?
katen-ka-za [31]

Answer:

d- it is an acid because it increases the concentration of hydronium ions

Explanation:

HCl; hydrochloric acid is an acid because it increases the concentration of hydronium ions when in solutions.

An acid is a substance that interacts with water to produce excess hydroxonium ions H₃O⁺ in an aqueous solution.

For example:

               HCl + H₂O → H₃O⁺ + Cl⁻

HCl is classified as a strong acid due to its complete ionization when in solutions.

3 0
3 years ago
Which mineral above would be the most difficult to scratch?
snow_tiger [21]
What are the choices
3 0
3 years ago
Read 2 more answers
In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area
storchak [24]

First we must write a balanced chemical equation for this reaction

Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)

The mole ratio for the reaction between HNO_3 and Na_2CO_3 is 1:2. This means 1 moles of Na_2CO_3 will neutralize 2 moles HNO_3. Now we find the moles of each reactant based on the mass and molar mass.

2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3

2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3

\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}

The Na_2CO_3 was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.

4 0
3 years ago
ASAP
sammy [17]

The answer is C.

The vast difference in electronegativity of the oxygen and hydrogen in water, the O-H bond is polar.

8 0
2 years ago
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