.91 is the largest number in that group.
Answer:
Cost of small box of oranges = 7
Cost of small box of oranges = 13
Step-by-step explanation:
Step 1) Let the cost of small box of oranges = x
Let the cost of small box of oranges = y
Step 2)
Equation 1) Matt sells 3 small boxes and 14 large boxes for Php. 203
3x + 14y = 203 -------------------(I)
Equation 2) Ming sells 11 small boxes and 11 large boxes for Php. 220
11x + 11y = 220 ----------------(II)
Step 3:
Multiply equation (I) by 11 and equation (II) by (-3).
(I)*11 33x + 154y = 2233
(II)*(-3) <u>-33x - 33y = -660 </u> {Now add and x will be eliminated}
121y = 1573
y = 1573/121
y = 13
Substitute y = 13 in equation (II)
11x + 11*13 = 220
11x + 143 = 220
11x = 220 - 143
11x = 77
x = 77/11
x = 7
<h2>
Answer with explanation:</h2>
Let p be the proportion of the correct answers.
As per given , we have

, since the alternative hypothesis is right tailed , so the test is a one -tailed test.
If the student gets 52 answers correct out of 80.
i.e. the proportion of correct answers : 
Test statistic : 

P-value :
[ by using p-value table for z (right-tailed)]
Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.
Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.
63.27 % of fishes are gold fish
<h3><u>Solution:</u></h3>
Given that out of 49 fish, 31 are goldfish
To find: percent of gold fish
The percent of gold fish is calculated by dividing number of goldfish by total number of fish multiplied by 100
<em><u>The percentage of gold fish is given by formula:</u></em>

From given information,
total number of fish = 49
number of gold fish = 31
Substituting the values in formula, we get

Therefore, approximately 63.27 % of fishes are goldfish
Answer:
0.8745.
Step-by-step explanation:
P(success) = 0.09 and P(failure) = 1 - 0.09 = 0.91.
P( at least 6 failures) = P( less than 2 successes)
= 7C0 (0.09)^0 (0.91)^7 + 7C1 (0.09)(0.91)^6
= 0.5168 + 0.3577
= 0.8745.