Jaquelyn wants to start getting to school on time more often. She is looking at some of her habits.
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Every value{0.01, 0.29, 85%} can represent the probability of an event occurring except option d that is 1.5.
Given to us,
a.)
b.) 0.29
c.) 85%
d.)
The probability help us to know about the probability of specific events occurring.
For a sure event, the probability is always 1,
while for an event that will never happen the probability is always 0.
Thus, probability(p), .
Now looking at the options,
a.) = 0.01
b.) 0.29
c.) 85% = 0.85
d.) = 1.5
Now comparing each option with .
Therefore, the only option which is not feasible is option d that is 1.5.
Hence, every value{0.01, 0.29, 85%} can represent the probability of an event occurring except option d that is 1.5.
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Answer:
Step-by-step explanation:
After graphing the function f(x) = we can see that the correct graph is the middle one in the picture. This is because with an x-input of 1 the value of 1/2 will stay the same and when multiplied by 4 it would give us a y-coordinate of 2 as seen in the middle graph. The y-coordinate keeps decreasing exponentially by half for every increase in the x-coordinate. A zoomed-in version of the graph can be seen in the attached picture below for a better understanding.
