Let the width of table B be w, and since area of table A = area of table B, then 6 2/3 x 3 1/2 = 4 1/4 x w [this is the required equation]
20/3 x 7/2 = 17/4 w
17/4 w = 70/3
w = 70/3 / 17/4 = 70/3 x 4/17 = 280/51 = 5 25/51
Answer:
The answer would be 21.99
Hope this helps :)
Step-by-step explanation:
Answer:
D) The manager should fail to reject the null hypothesis; there is not enough evidence to conclude that the number of unique daily listeners has changed.
Step-by-step explanation:
The scenario indicates the null hypotheses and alternative hypotheses are
Null hypotheses: The number of unique daily listeners hasn't changed.
Alternative hypotheses: The number of unique daily listeners has changed.
The null hypothesis is rejected if the calculated p-value is less significance level.
We are given that p-value is 0.0743 and confidence level=0.95.
Significance level =α=1-0.95=0.05.
As we can see the p-value is greater than significance level, so, we fail to reject the null hypotheses at 5% significance level.
Thus, we conclude at the 95% confidence level that the manager should fail to reject the null hypothesis; there is not enough evidence to conclude that the number of unique daily listeners has changed
I don't know if you still need help. but the answer is the first one.
