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laila [671]
2 years ago
9

The number of π molecular orbitals in a molecule is always equal to the number of ________. a. p orbitals used to construct the

π bonds b. hydrogen atoms in the molecule c. π bonds
Chemistry
1 answer:
Dmitrij [34]2 years ago
6 0

The number of π molecular orbitals in a molecule is always equal to the number of p orbitals used to construct the π bonds.

An electron's position and wave-like behavior within a molecule are described by a mathematical function called a molecular orbital. Chemical, as well as physical properties like the probability of locating an electron in a particular area, can be determined using this function.

A molecular orbital would be created when two atomic orbitals cross one other along the internuclear axis. A molecular orbital is created when two atomic orbitals cross each other sideways.

Therefore, the number of π molecular orbitals in a molecule is always equal to the number of p orbitals used to construct the π bonds.

Hence, the correct answer will be option (a).

To know more about molecular orbitals

brainly.com/question/13265432

#SPJ4

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Use the following equation to answer the questions and please show all work.
DIA [1.3K]

Answer:

a.36 g of water is produced.

b.64 g of O_{2} is consumed.

Explanation:

The reaction is 2H_{2} + O_{2}⇒2H_{2}O

a.

Given,

Weight of H_{2} reacted = 4g

Weight of 1 mole of H_{2} = 2\times1 = 2g

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Also given,

Weight of O_{2} reacted = 32 g

Weight of 1 mole of O_{2} = 2\times16 = 32 g

Therefore no. of moles of O_{2} reacted = \frac{32}{32} = 1

We know that 2 moles of Hydrogen reacts with 1 mole of Oxygen to give 2 moles of water,

As we took 2 moles of Hydrogen and 1 mole of Oxygen,

Directly,from the equation we can tell 2moles of water will be produced.

Therefore no. of moles of H_{2} O produced = 2

Weight of 1 mole of water = 2\times 1+16 = 18

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b.

Given ,

72 g of H_{2}O is produced.

So,

no. of moles of H_{2}O produced =\frac{72}{18} = 4 moles

From equation For every 2 moles of water formed , 1 mole of oxygen must be required.

So for producing 4 moles of water,

No. of moles of Oxygen required = 2 moles.

Therefore weight of O_{2} reacted = 2\times32 = 64 g

Method 2:

Given,

8 g of H_{2} has reacted.

So,

no. of moles of H_{2} reacted = \frac{8}{2} = 4 moles.

From equation , we know that For every 2 moles of H_{2} reacted,1 mole of O_{2} will react.

Therefore,

No. of moles of O_{2} that reacts with 4 moles of H_{2} = 2\times1 = 2 moles

Therefore the weight of O_{2} reacted = 2\times 32 = 64 g

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