Answer:
mass of HCl = 3.65 g
Explanation:
Data Given:
Moles of hydrochloric acid HCl = 0.1 mole
Mass in grams of hydrochloric acid HCl = ?
Solution:
Mole Formula
no. of moles = Mass in grams / molar mass
To find Mass in grams rearrange the above Formula
Mass in grams = no. of moles x molar mass . . . . . . . (1)
Molar mass of HCl = 1 + 35.5 = 36.5 g/mol
Put values in equation 1
Mass in grams = 0.1 mole x 36.5 g/mol
Mass in grams = 3.65 g
mass of HCl = 3.65 g
Answer:
Properties of metals, worksheet 6.1
Explanation:
Answer:
k = -0.09165 years^(-1)
Explanation:
The exponential decay model of a radioactive isotope is generally given as;
A(t) = A_o(e^(kt))
Where;
A_o is quantity of isotope before decay, k is decay constant and A(t) is quantity after t years
We are given;
A_o = 5 kg
A(10) = 2kg
t = 10 years
Thus;
A(10) = 2 = 5(e^(10k))
Thus;
2 = 5(e^(10k))
2/5 = (e^(10k))
0.4 = (e^(10k))
In 0.4 = 10k
-0.9164 = 10k
k = -0.9164/10
k = -0.09165 years^(-1)
Answer: Thus the volume of the balloon at this altitude is 419 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
= initial pressure of gas = 751 mm Hg
= final pressure of gas = 495 mm Hg
= initial volume of gas = 340 L
= final volume of gas = ?
= initial temperature of gas = ![30^oC=273+30=303K](https://tex.z-dn.net/?f=30%5EoC%3D273%2B30%3D303K)
= final temperature of gas = ![-27^oC=273-27=246K](https://tex.z-dn.net/?f=-27%5EoC%3D273-27%3D246K)
Now put all the given values in the above equation, we get:
![\frac{751\times 340}{303}=\frac{495\times V_2}{246}](https://tex.z-dn.net/?f=%5Cfrac%7B751%5Ctimes%20340%7D%7B303%7D%3D%5Cfrac%7B495%5Ctimes%20V_2%7D%7B246%7D)
![V_2=419L](https://tex.z-dn.net/?f=V_2%3D419L)
Thus the volume of the balloon at this altitude is 419 L