Answer:
V = 1.79 L
Explanation:
Given data:
Volume of gas = ?
Number of moles of gas = 0.080 mol
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × V = 0.080 mol × 0.0821 atm.L/ mol.K × 273.15 K
V = 1.79 atm.L / 1 atm
V = 1.79 L
Answer:
W has the most potential energy
I think the answer is c. I'm sorry if I'm wrong. I hope this helps also
Answer:
The total applied force on the trolley is 5 N toward the North.
Explanation:
In this problem, Ben is pushing the trolley to north and Gary is pushing it to south. So both the forces are acting 180° opposite to each other. As force is a vector quantity, the net force or total force acting on any object should be calculated by vector addition of number of forces along with their directions. So in this case, if we consider the force Ben is applying as F1 and the force Gary is applying as F2 on the trolley. Then the net or total force acting on the trolley will be
. This is because, F1 and F2 are acting opposite to each other in direction.Thus,
.
So the total force acting on the trolley is 5 N and it is toward the north direction.
Cofactors:
A. Coenzyme A (CoA-SH)
B. NAD+
C. Thiamine pyrophosphate (TPP)
D. FAD
E. Lipoic acid in oxidized form
Roles:
E... Attacks and attaches to the central carbon in pyruvate.
A...Oxidizes FADH2.
C...Accepts the acetyl group from reduced lipoic acid.
D... Oxidizes the reduced form of lipoic acid.
B... Initial electron acceptor in oxidation of pyruvate.