How do electrons transition between energy levels?

1 answer:

7 0

The electron with its extra packet of energy becomes excited, and promptly moves out of its lower energy level and takes up a position in a higher energy level.

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Can someone please please help me with the first two !!!! I really need to turn this in !!!!!

kati45 [8]

Answer:

Be Electron configuration: 1s2 2s2

Be Orbital Diagram: \//\ \//\ (it would be little arrows going up and down to show the spins)

F Electron Configuration: 1s2 2s2 2p5

F Orbital Diagram: \//\ \//\ \//\ \//\ \/

7 0

2 years ago

Matter is made up of heat energy and ___________energy?

ella [17]

You’re correct, matter is made up of heat energy and chemical energy

all matter contains heat because it is the result of the movement of atoms, molecules, or ions in solids, liquids, and gases.

all matter also contains chemical energy. chemical energy is stored in the bonds of chemical compounds so atoms and molecules are held together by chemical energy

hope this helps :)

3 0

2 years ago

The _________________ are either elements or compounds which are present prior to a chemical reaction.

mr Goodwill [35]

Reactants would be the missing word in the sentence because they make up the products in a chemical reaction

3 0

2 years ago

Read 2 more answers

The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of

denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

$Kb=\frac{[IBH^+][OH^-]}{[IB]}$

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

$pOH=14-8.20=5.80$

$[OH^-]=10^{-5.8}=1.585x10^{-6}M$

$Kb=10^{-5.20}=6.31x10^{-6}$

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

$6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}$