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worty [1.4K]
2 years ago
12

How to balance the equation Mg2+HO2=Cu3O+H2​

Chemistry
1 answer:
Mariulka [41]2 years ago
6 0
I think the answer is 2Mg + H2O4 = Cu12O4 + 2H

I’m really not sure though so it might be wrong… I’m not the best at balancing equations lol
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¿Por qué la letra hache de “pH” se escribe con mayúscula?
Amiraneli [1.4K]
La 'H' en el pH se refiere a la concentración de iones de hidrógeno en una solución. El símbolo químico del hidrógeno es H y siempre está en mayúscula. La 'p' es solo un símbolo matemático que significa 'logaritmo negativo'.
7 0
3 years ago
What did Kwang Jeon discover when researching amoeba infected by bacteria?
defon
<span>Kwang Jeon observed that Amoeba had been attacked by a bacterial infection, and lots of the Amoeba had died. However, some survived and continued to reproduce. After investigating the remaining Amoeba and their offspring, he noticed they were very healthy. He thought maybe they were able to fight off the bacteria, but instead, he found they were still infected with the bacteria but were not dying. The bacteria were no longer making the Amoeba sick. Then, he killed off the bacteria using antibiotics and was surprised to see that the Amoeba also died. It seemed the Amoeba and bacteria had formed a relationship in which they both needed each other to survive. After researching, Jeon found that the bacteria made a protein that the Amoeba needed to survive. </span>
6 0
3 years ago
Which technique would be best for separating sand and water?
ipn [44]

Answer:

A. filtration

Hope it helps

3 0
3 years ago
Calculate the mass of water vapor that is produced by the reaction: 
Reika [66]

Answer:

m_{H_2O}=0.353gH_2O

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to identify the required limiting reactant by calculating the moles of water vapor produced by each reactant, CO2 and KOH, as shown below:

1.4gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molH_2O}{1molCO_2}=0.0318mol  H_2O\\\\2.2gKOH*\frac{1molKOH}{56.11gKOH}*\frac{1molH_2O}{2molKOH}=0.0196mol  H_2O

In such a way, since 2.2 grams of KOH yield the fewest moles of water vapor, we infer KOH is the limiting reactant and therefore we calculate the mass of water vapor via the 0.0196 moles we obtained:

m_{H_2O}=0.0196molH_2O*\frac{18.02gH_2O}{1molH_2O}=0.353gH_2O

Regards!

8 0
3 years ago
An unknown compound contains only carbon, hydrogen, and oxygen (cxhyoz). combustion of 3.50 g of this compound produced 5.13 g o
harkovskaia [24]

The formula for determining the number of moles is:

number of moles = \frac{mass}{molecular weight}

Mass of compound = 3.5 g

Mass of carbon dioxide produced = 5.13 g

Mass of water produced = 2.10 g

Molecular weight of water, H_2O = 18 g/mol

Substituting the values in above equation:

number of moles = \frac{2.10 g}{18 g/mol}= 0.11667 mole

Since, 1 mole of water contains 2 moles of hydrogen therefore, number of moles of hydrogen = 0.11667 mole\times 2 = 0.23334 mole


4 0
3 years ago
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