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mote1985 [20]
1 year ago
12

2+X/9 = 5x-6/27 SOLVE.

Mathematics
1 answer:
oksano4ka [1.4K]1 year ago
6 0

Answer:

x = 6

Step-by-step explanation:

First, we need to cross multiply on both sides, which gives us:

9 * (5x - 6) = 27 * (2 + x)

45x - 54 = 54 + 27x

Now, we want to isolate x on either side.

We can substract 54 from both sides:

(45x - 54 = 54 + 27x) - 54

45x - 108 = 27x

We then subtract 45 from both sides:

(45x - 108 = 27x) - 45

-108 = -18x

Finally, we divide both sides by -18:

(-108 = -18x) / -18

6 = x

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c) A response of 4.4 represents the first ​quartile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5.9

Standard Deviation, σ = 2.2

We assume that the distribution of response is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) We have to find the value of x such that the probability is 0.92

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.92

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = 1.405\\x = 8.991 \approx 8.9

A response of 8.9 represents the 92nd ​percentile.

b) We have to find the value of x such that the probability is 0.62

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.62

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = 0.305\\x = 6.571 \approx 6.6

A response of 6.6 represents the 62nd ​percentile.

c) We have to find the value of x such that the probability is 0.25

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.25

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = -0.674\\x = 4.4172 \approx 4.4

A response of 4.4 represents the first ​quartile.

4 0
3 years ago
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