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2 years ago

2+X/9 = 5x-6/27 SOLVE.

Mathematics

1 answer:

oksano4ka [1.4K]2 years ago

6 0

Answer:

x = 6

Step-by-step explanation:

First, we need to cross multiply on both sides, which gives us:

9 * (5x - 6) = 27 * (2 + x)

45x - 54 = 54 + 27x

Now, we want to isolate x on either side.

We can substract 54 from both sides:

(45x - 54 = 54 + 27x) - 54

45x - 108 = 27x

We then subtract 45 from both sides:

(45x - 108 = 27x) - 45

-108 = -18x

Finally, we divide both sides by -18:

(-108 = -18x) / -18

6 = x

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X intercept: (-4)
y intercept: (8)

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3 years ago

A recipe that makes 4 servings calls for Two-thirds cup of flour. How much flour is required to make 20 servings? 6 cups 3 and o

Vlad [161]

Answer:

3 1/3 cups of flour

Step-by-step explanation:

20/4 = 5

20 servings is 5 times 4 servings, so you need 5 times the amount of ingredients.

5 * 2/3 = 10/3 = 3 1/3

Answer: 3 1/3 cups of flour

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3 years ago

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timama [110]

Answer:

The answer is D. -3, 6, 11

Step-by-step explanation:

A coefficient is a number used to multiply a variable.

Example: 6z means 6 times z, and "z" is a variable, so 6 is a coefficient. Variables with no number have a coefficient of 1.

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3 years ago

Write the equation in standard form for the circle with center (0, – 10) and radius 6.

Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: $(x-h)^2+(y-k)^2=r^2$

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

$(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36$

So, equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

5 0

3 years ago

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is

$F_{critical} = 1.8608$

Generally the test statistics is mathematically represented as

$F = \frac{s_1^2 }{s_2^2}$

=> $F = \frac{8324 }{2862}$

=> $F = 2.9085$

Generally from the value obtained we see that $F > F_{critical }$ Hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is sufficient evidence to support the researchers claim

4 0

3 years ago