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1 year ago

PLS HELP

Mathematics

2 answers:

bekas [8.4K]1 year ago

7 0

D. The input value can always be any number

bezimeni [28]1 year ago

6 0

Answer:

Step-by-step explanation:

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An oil drilling company is drilling a hole. The elevation of the bottom of the hole changes by feet each day. After a certain nu

marin [14]

Answer:

option.D

Step-by-step explanation:

each day it changes by $-73\frac{1}{4}$

so for two days , the elevation becomes $-73\frac{1}{4}$ + $-73\frac{1}{4}$

for 3 days : $-73\frac{1}{4}$ + $-73\frac{1}{4}$ + $-73\frac{1}{4}$

so, for n days, $-73\frac{1}{4}$ + ........ n times

= n* $-73\frac{1}{4}$

therefore, for x days, elevation = x* $-73\frac{1}{4}$

as it is given that after certain days this elevation has reached $-366\frac{1}{4}$

so, x* $-73\frac{1}{4}$ = $-366\frac{1}{4}$

3 0

3 years ago

Please help me with this question....

AVprozaik [17]

Answer:

$63.63 {m}^{2}$

Step-by-step explanation:

$area \: = \pi {r}^{2} \\ = 3.142(4.5) {}^{2} \\ = 63.63m {}^{2}$

7 0

3 years ago

A movie theater problem I need help with

Sever21 [200]

What's 18 × 15 ?

Hint : 270

4 0

3 years ago

Read 2 more answers

2. The sum of two numbers is 30. Determine the two numbers if their product is a maximum.

SCORPION-xisa [38]

Answer:

X+y=30

X=30-y

Z=yx

Z=y(30-y)

D/dy

z=30–2y

At max 30–2y=0

2y=30 Y=15

Therefore x=15

Step-by-step explanation:

5 0

2 years ago

A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe

djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

$\mathbf{h(t) = -16t^2 + 160t}$

Differentiate the function with respect to t

$\mathbf{h'(t) = -32t + 160}$

Set to 0

$\mathbf{h'(t) = -32t + 160 = 0}$

So, we have:

$\mathbf{-32t + 160 = 0}$

Collect like terms

$\mathbf{-32t =- 160 + 0}$

$\mathbf{-32t =- 160}$

Solve for t

$\mathbf{t = \frac{- 160}{-32}}$

$\mathbf{t = 5}$

Hence, the projectile reaches the maximum after 5 seconds