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pantera1 [17]
3 years ago
5

Bob is having a party and wants to order some cakes.

Mathematics
1 answer:
Dmitry [639]3 years ago
7 0

Answer: There isn't a possible way you can really answer this question because I don't know how much one piece cost in the first place , but if I had to guess I would say around 50-80 dollars for a cake is enough for 57 guests.

explanation: I say this because I know usually cakes for a decent amount of people are around 50-80 dollars.

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The Air Quality Index, or AQI, measures how polluted the air is in your city and assigns a number based on the quality of the ai
tatuchka [14]

Answer:

it is actually c.135 days on edge just took the test

Step-by-step explanation:

took the test

3 0
3 years ago
given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these
lesya [120]

Answer:


Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

a_{n}=a_{n-1}*r

so comparing it with the given recursive formula a_{n}=a_{n-1}*-4

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.

Explicit Formula =-2*(-4)^{n-1}

2) Comparing the given recursive formula a_{n}=a_{n-1}*-2

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-2

8th term= a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.

Explicit Formula =-4*(-2)^{n-1}

3)Comparing the given recursive formula a_{n}=a_{n-1}*3

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =3

8th term= a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.

Explicit Formula =-1*(3)^{n-1}

4)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.

Explicit Formula =3*(-4)^{n-1}

5)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.

Explicit Formula =-4*(-4)^{n-1}

6)Comparing the given recursive formula a_{n}=a_{n-1}*-2

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-2

8th term= a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.

Explicit Formula =3*(-2)^{n-1}

7)Comparing the given recursive formula a_{n}=a_{n-1}*-5

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-5

8th term= a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.

Explicit Formula =4*(-5)^{n-1}

8)Comparing the given recursive formula a_{n}=a_{n-1}*-5

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-5

8th term= a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.

Explicit Formula =2*(-5)^{n-1}

6 0
3 years ago
Write a function rule for the area of rectangle whose length is 2ft more than its width. What is the area of the rectangle when
Marianna [84]

According to the problem, the length is 2 feet more than its width, which is expressed as the following function

l=w+2

If the width is x, then the length is x+2.

We can express the following function for the area

A(x)=x(x+2)

Let's replace the width x = 11 ft.

A(11)=11\cdot(11+2)=11(13)=143<h2>Hence, the area is 143 square feet. </h2><h2>The function for the area is</h2>A(x)=x(x+2)

Where x represents the width.

3 0
1 year ago
Does anyone know this? I’m really stuck
S_A_V [24]

<em>p = 21</em>

Step-by-step explanation:

When you have a midsegment, the base is going to be two times as large as the midsegment. You can find the midsegment if you multiply it by two and set it equal to the base. I have attached a photo below that may help you.

This is the equation we will be using.

2(p-13)=p-5

Now let's solve! Let's start by distributing the 2 by what's in the parentheses.

2p-26=p-5

Subtract p from both sides.

p-26=-5

Add 26 to both sides.

<u>p = 21</u>

7 0
3 years ago
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