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AlladinOne [14]
3 years ago
6

-4x^3+21x^2-23x+6 / (x-4)

Mathematics
2 answers:
777dan777 [17]3 years ago
8 0
\frac{-4x^3+21x^2-23x+6}{x-4} = \frac{(-4 x^{2} +5x-3)(x-4)-6}{x-4}
hoa [83]3 years ago
6 0
        <u>           -4x² +   5x - 3</u>
x - 4|-4x³ + 21x² - 23x + 6
      <u>-(-4x³ + 16x²)
</u>                 <u> </u>    5x² - 23x
                 <u>-(-5x² - 20x)</u>
                              -3x +   6
                            <u>-(-3x + 12)</u>
                                        -6
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Hello,

1)
a_{1}=7
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a_{3}=7*3^2

a_{n}=7*3^{n-1}

s=a_{1}+a_{2}+a_{3}+a_{4}+a_{5}=7*(1+3^1+3^2+3^3+3^4)
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