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AlladinOne [14]
3 years ago
6

-4x^3+21x^2-23x+6 / (x-4)

Mathematics
2 answers:
777dan777 [17]3 years ago
8 0
\frac{-4x^3+21x^2-23x+6}{x-4} = \frac{(-4 x^{2} +5x-3)(x-4)-6}{x-4}
hoa [83]3 years ago
6 0
        <u>           -4x² +   5x - 3</u>
x - 4|-4x³ + 21x² - 23x + 6
      <u>-(-4x³ + 16x²)
</u>                 <u> </u>    5x² - 23x
                 <u>-(-5x² - 20x)</u>
                              -3x +   6
                            <u>-(-3x + 12)</u>
                                        -6
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Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=11x−3 and CE=12−4x. Find the length of AC.
Oxana [17]

Answer:

AC=16 units

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.  It was given that diagonals AC and BD intersect at point E.

This implies that: AE=CE.

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pashok25 [27]

Answer:

The answer is 68°

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • A right angled-triangle IGH.
  • where, m∠G = 90°
<h3><u>To </u><u>Find</u>;</h3>
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We know that

tan θ = Opp ÷ Adj

tan θ = 5 ÷ 2

tan θ = 2.5

tan θ = 68.2 ≈ 68

We know that tan 68 = 2.5

Thus, The m∠I is 68°

<u>-TheUnknownScientist 72</u>

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