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AlladinOne [14]
3 years ago
6

-4x^3+21x^2-23x+6 / (x-4)

Mathematics
2 answers:
777dan777 [17]3 years ago
8 0
\frac{-4x^3+21x^2-23x+6}{x-4} = \frac{(-4 x^{2} +5x-3)(x-4)-6}{x-4}
hoa [83]3 years ago
6 0
        <u>           -4x² +   5x - 3</u>
x - 4|-4x³ + 21x² - 23x + 6
      <u>-(-4x³ + 16x²)
</u>                 <u> </u>    5x² - 23x
                 <u>-(-5x² - 20x)</u>
                              -3x +   6
                            <u>-(-3x + 12)</u>
                                        -6
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Kira, goran, &amp; joe sent a total of 90 text messages during the weekend. Goran sent 5 fewer messages than Kira. Joe sent 3 ti
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Step-by-step explanation:

Let be "k" the number of text messages that Kira sent during the weekend, "g" the number of text messages that Gora sent during the weekend and "j" the number of text messages that Joe sent during the weekend.

We know know that they sent a total of 90 text messages then:

k+g+j=90

Goran sent 5 fewer messages than Kira. This is:

g=k-5

And Joe sent 3 times as many messages as Kira. Then:

j=3k

The steps to solve this are:

- Substitute the second equation and the third equatio into the first equation  and then solve for "k":

k+(k-5)+(3k)=90\\\\5k-5=90\\\\5k=90+5\\\\k=\frac{95}{5}\\\\k=19

- Substitute this value into the second equation to find "g":

g=19-5=14

- Substitute the value of "k" into the third equation to find "j":

j=3(19)=57

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