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Rom4ik [11]
2 years ago
9

During transpeptidation, nucleophilic attack occurs between the α-amine group in the ____ site and the esterified carbon in the

____ site.
Biology
1 answer:
kap26 [50]2 years ago
7 0

During transpeptidation, nucleophilic attack occurs between the α-amine group in the A site and the esterified carbon in the P site.

<h3>What is a transpeptidation?</h3>
  • A chemical process in which an amino acid residue or a peptide residue is transferred from one amino molecule to another (as in the reversible conversion of one peptide to another by a protease).
  • The binding of transpeptidase PBPs inhibits peptidoglycan production.
  • Transpeptidase is a bacterial enzyme that cross-links peptidoglycan strands to build stiff cell walls. A liver enzyme called gamma-glutamyl transpeptidase. Transpeptidase D-glutamyl.

To learn more about nucleophilic attacks from the given link

brainly.com/question/27178362

#SPJ4

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A man borrowed money at a bank $1400 at the rate o 3% for 3 years. a) Find the simple interest b) Find th total money repaid aft
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b) The total money repaid after 3 years is $1526.

Step-by-step explanation:

A man borrowed money at a bank $1400 at the rate o 3% for 3 years.

a) Find the simple interest

\longrightarrow{\sf{\red{S.I =  \dfrac{PRT}{100}}}}

  • → S.I = Simple Interest
  • → P = Principal
  • → R = Rate
  • → T = Time

Substituting all the given values in the formula to find the Simple Interest :

\longrightarrow{\sf{S.I =  \dfrac{PRT}{100}}}

\longrightarrow{\sf{S.I =  \dfrac{P \times R \times T}{100}}}

\longrightarrow{\sf{S.I =  \dfrac{1400 \times 3 \times 3}{100}}}

\longrightarrow{\sf{S.I =  \dfrac{14 \cancel{00}\times 3 \times 3}{1 \cancel{00}}}}

\longrightarrow{\sf{S.I = 14 \times 3 \times 3}}

\longrightarrow{\sf{S.I = 42 \times 3}}

\longrightarrow{\sf{S.I = 126}}

\star{\underline{\boxed{\pmb{\sf{S.I = \$126}}}}}

Hence, the simple interest is $126.

━━━━━━━━━━━━━━━━

b) Find the total money repaid after 3 years

\dashrightarrow{\sf{\pink{A = P + S.I }}}

  • → A = Amount
  • → P = Principal
  • → S.I = Simple Interest

Substituting all the given values in the formula to find the Amount :

\dashrightarrow{\sf{A = P + S.I }}

\dashrightarrow{\sf{A = 1400 + 126 }}

\dashrightarrow{\sf{A = 1526}}

\star{\underline{\boxed{\pmb{\sf{A = \$1526}}}}}

Hence, the total money repaid after 3 years is $1526.

\rule{300}{2.5}

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