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3 years ago

Van der Waals forces can best be described as the attractive or repulsive forces that are formed

2 answers:

5 0

Vander Waals forces can best be described as the attractive or repulsive forces that are formed during dipole-dipole interactions between molecules.

Vander Waals forces arises from interaction between uncharged atoms or molecules and these are formed during dipole-dipole interactions between molecules. Vander waal forces are weak forces that vanishes when molecules moves apart.

dem82 [27]3 years ago

3 0

Correct answer: by a random, short-lived redistribution of electrons.

van der Waal's forces are the weak intermolecular forces of attraction or repulsions that are seen in all molecules, when they come close to each other. These forces of attraction or repulsion are due to the momentary charges that develop between the electron clouds of one atom and the nuclei of the other atom. Therefore, the van der Waal's forces are due to the instantaneous dipoles that are produced between two atoms close to each other, due to the redistribution of electron clouds.

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Select the correct answer.

777dan777 [17]

For this one B is the correct one

6 0

3 years ago

Read 2 more answers

Some commercially available algaecides for swimming pools claim to contain 7% copper. Could the method used in this experiment t

AleksandrR [38]

Answer:

Explanation:

7% copper implies 7 w/v%(weight/volume %) of copper. This implies a 100 mL algaecide arrangement contains 7 grams of copper.
Henceforth we have a thought of the measure of copper that ought to be available in a given example of algaecide.
Indeed, even a 1 mL algaecide test is sufficient to discover the percentage of copper in it.
so a 25mL sample of algaecide must have around 1.75g of copper.

4 0

4 years ago

The standard reduction potentials of the following half-reactions are given in Appendix E in the textbook:

german

Answer:

For 1: The largest positive cell potential is of cell having 1st and 4th half reactions.

For 2: The standard electrode potential of the cell is 1.539 V

For 3: The smallest positive cell potential is of cell having 3rd and 4th half reactions. The standard electrode potential of the cell is 0.46 V

Explanation:

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

We are given:

$Ag^++(aq.)+e^-\rightarrow Ag(s);E^o_{Ag^+/Ag}=0.799V\\\\Cu^{2+}+(aq.)+2e^-\rightarrow Cu(s);E^o_{Cu^{2+}/Cu}=0.337V\\\\Ni^{2+}(aq.)+2e^-\rightarrow Ni(s);E^o_{Ni^{2+}/Ni}=-0.28V\\\\Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o_{Cr^{3+}/Cr}=-0.74V$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Cell having 1st and 2nd half reactions:

Silver has higher electrode potential. So, this will undergo reduction reaction and act as anode. Copper will undergo oxidation reaction and act as cathode.

$E^o_{cell}=0.799-0.337=0.462V$

Cell having 1st and 3rd half reactions:

Silver has higher electrode potential. So, this will undergo reduction reaction and act as anode. Nickel will undergo oxidation reaction and act as cathode.

$E^o_{cell}=0.799-(-0.28)=1.079V$

Cell having 1st and 4th half reactions:

Silver has higher electrode potential. So, this will undergo reduction reaction and act as anode. Chromium will undergo oxidation reaction and act as cathode.

$E^o_{cell}=0.799-(-0.74)=1.539V$

Cell having 2nd and 3rd half reactions:

Copper has higher electrode potential. So, this will undergo reduction reaction and act as anode. Nickel will undergo oxidation reaction and act as cathode.

$E^o_{cell}=0.337-(-0.28)=0.617V$

Cell having 3rd and 4th half reactions:

Nickel has higher electrode potential. So, this will undergo reduction reaction and act as anode. Chromium will undergo oxidation reaction and act as cathode.

$E^o_{cell}=-0.28-(-0.74)=0.46V$

Hence,

For 1: The largest positive cell potential is of cell having 1st and 4th half reactions.

For 2: The standard electrode potential of the cell is 1.539 V

For 3: The smallest positive cell potential is of cell having 3rd and 4th half reactions. The standard electrode potential of the cell is 0.46 V

8 0

4 years ago

Is the igneous rock destructive or constructive?

sammy [17]

This certain type of rock is constructive, not only from the fact that it was made up from earthly habits. But also it breaks down very easily, which can help the environment. Therefore a sedimentary rock is constructive.

5 0

4 years ago

After 4 half-lives 10 grams of uranium remains. How much uranium did you start with?

Free_Kalibri [48]

Answer:

i think 40 grams

Explanation:

4 0

3 years ago