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2 years ago

3 Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

Chemistry

1 answer:

Zepler [3.9K]2 years ago

7 0

Answer:

A shape has 2 pairs of parallel sides and no right angles. What shape is it?

Trapezoid

Parallelogram

Square

RectangleA shape has 2 pairs of parallel sides and no right angles. What shape is it?

Trapezoid

Parallelogram

Square

Rectangle

Explanation:

A shape has 2 pairs of parallel sides and no right angles. What shape is it?

Trapezoid

Parallelogram

Square

Rectangle

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The reaction is called chain reaction when

Maru [420]

Answer:

c. it involves a series of steps, each of which generates a reactive intermediate that brings about the next step

Explanation:

A chain reaction consist of many repeating steps. Chain reaction will never stop until all the reactant has been exhausted. It is more of a cycle of reaction that generate a reactive intermediate that brings about the next step.

Example of a chain reaction is the chlorination of methane.

CH4 + Cl2 ↔ CH3Cl + HCl

CH3Cl + Cl2 ↔ CH2Cl2 + HCl

CH2Cl2 + Cl2 ↔ CHCl3 + HCl

CHCl3 + Cl2 ↔ CCl4 + HCl

7 0

3 years ago

A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l

madreJ [45]

Explanation:

From first source, kinetic energy ( $K.E_{1}$ ) ejected is 1 eV and wavelength of light is $\lambda$ .

From second source, kinetic energy ( $K.E_{2}$ ) ejected is 4 eV and wavelength of light is $\frac{\lambda}{2}$ .

Relation between work function, wavelength, and kinetic energy is as follows.

K.E = $\frac{hc}{\lambda} - \phi$

where, h = Plank's constant = $6.63 \times 10^{-34}$ J.s

c = speed of light = $3 \times 10^{8}$ m/s

Also, it is known that 1 eV = $1.6 \times 10^{-19}$ J

Therefore, substituting the values in the above formula as follows.

From first source,

$K.E_{1}$ = $\frac{hc}{\lambda} - \phi$

1 eV = $1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi$

$1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (1)

From second source,

$K.E_{2}$ = $\frac{hc}{\lambda} - \phi$

$4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi$

$6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (2)

Now, divide equation (2) by 2. Therefore, it will become

${6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}$

$3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}$ ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

$1.6 \times 10^{-19} = \frac{\phi}{2}$

$\phi$ = $3.2 \times 10^{-19}$

= 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0

3 years ago

Does corrosion occur when iron nail is in salt water

yarga [219]

Answer:

Yes

Explanation:

: The corrosion of iron indicates a chemical change in the metal. ... Where salt is present, electrochemical corrosion occurs, and the protective oxide film does not form, thus the corrosion (buildup of rust) continues unchecked. Your iron nail will indeed rust more quickly and severely in salt water.

5 0

3 years ago

A dry gas at a temperature of 67.5 C and a pressure of 882 torr occupies a volume of 242.2 mL. What will be the volume of the ga

masya89 [10]

Answer:

265 mL is the new volume for the gas

Explanation:

We decompose the Ideal Gases Law in order to find the answer of this question: P . V = n . R . T

We can propose the formula for the 2 situations, where n remains constant.

R refers to 0.082 L.atm/mol.K which is physic constant.

We convert the temperature to Absolute value:

67.5°C + 273 = 340.5 K

80°C + 273 = 353 K

We convert the volume to L → 242.2 mL . 1 L/1000 mL = 0.2422 L

We convert the pressure values to atm:

882 Torr . 1 atm/ 760 Torr = 1.16 atm

840 Torr . 1atm / 760 Torr = 1.10 atm

P₁. V₁ / T₁ = P₂ . V₂ / T₂ → Let's replace data:

1.16 atm . 0.2422L / 340.5K = 1.10 atm . V₂ / 353 K

(1.16 atm . 0.2422L / 340.5K) . 353K = 1.10 atm . V₂

V₂ = 0.291 L.atm / 1.10 atm → 0.2647 L ≅ 265 mL

4 0

3 years ago

2A(g) + B(l) ⇌ 3C(aq) + D(s)

makvit [3.9K]

Answer:

[(0.75)^3(0.25)]÷[(0.50)^2(0.75)]

Explanation:

toppr dot com

8 0

3 years ago