Answer:
yes it is true they apply necessary safety measures
Mass spectrometry was discovered by Francis Aston, a British Physicist, in 1919. This involves separating mixtures of substances into their components and transforming them into beams of particles and subsequently, bending them with the use of electricity and magnetism to come up with a spectrum that is inherently unique for every individual atoms for easy identification.
Answer:
The mass number tells us the number (the sum of nucleons) of protons and neutrons in the nucleus of an atom. The atomic number (also known as the proton number) is the number of protons found in the nucleus of an atom. It is traditionally represented by the symbol z
Explanation:
Answer:
4 monochlorination products can be formed.
Explanation:
Constitutional isomers : These are those compounds with same molecular formula but different atomic arrangement.For example: butane and 2-methly-propane.
On monochlorination of 2 methyl-butane we will have four possibilities of product which will be constitutional isomers of each other:
- 1-chloro-3-methyl butane :

- 2-chloro-3-methyl butane :

- 2-chloro-2-methyl butane

- 1-chloro-2-methyl butane

Answer:
The concentration of the standard NaOH solution is 0.094 moles/L.
Explanation:
In the titration, the equivalence point is defined as the point where the moles of NaOH (the titrant) and KHP (the analyte) are equal:
moles of NaOH = moles of KHP
![[NaOH]xV_{NaOH} = moles of KHP](https://tex.z-dn.net/?f=%5BNaOH%5DxV_%7BNaOH%7D%20%3D%20moles%20of%20KHP)
![[NaOH] = \frac{moles of KHP}{V_{NaOH}}](https://tex.z-dn.net/?f=%5BNaOH%5D%20%3D%20%5Cfrac%7Bmoles%20of%20KHP%7D%7BV_%7BNaOH%7D%7D)
The
is 40.82mL = 0.04082L and the moles of KHP are

Replacing at the first equation:
![[NaOH] = \frac{3.827x10^{-3}moles}{0.04082L} = 0.094 moles/L](https://tex.z-dn.net/?f=%5BNaOH%5D%20%3D%20%5Cfrac%7B3.827x10%5E%7B-3%7Dmoles%7D%7B0.04082L%7D%20%3D%200.094%20moles%2FL)