Watershed....water....river.....streams....oceans....contaminate....nitrogen....phosphorous....subsidence...Thats the order...please give brainliest......
175.8 g NaCl to moles:
(175.8 g)/(58.44 g/mol) = 3.008 mol NaCl
Molarity = moles of solute/volume of solution in liters
(3.008 mol NaCl)/(1.5 L) = 2.0 M.
The molarity of this solution would be 2.0 M.
The answer the the question is 22
To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:
C = 68.75 g
H = 10.90 g
O = 20.35 g
We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
O = 20.35 g / 16 g/mol = 1.27 mol
C = 5.72 mol / 1.27 mol = 5
H = 10.79 mol / 1.27 mol = 8
O = 1.27 mol / 1.27 mol = 1
C5H8O
