Q = mCΔT
Q is heat in joules, m is mass, C is specific heat, and delta T is change in temp
2099 J = (40.27g)(C)(148.5 - 24.8) = .421 J / gram K
Answer:
Moles of Hydrogen produced is 5 moles
Explanation:
The balanced Chemical equation for reaction between zinc and sulfuric acid is :
![Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)](https://tex.z-dn.net/?f=Zn%28s%29%20%2B%20H_%7B2%7DSO_%7B4%7D%28aq%29%20%5Crightarrow%20ZnSO_%7B4%7D%28aq%29%20%2B%20H_%7B2%7D%28g%29)
This equation tells that ; when 1 mole of Zn react with 1 mole of sulfuric acid, it produces 1 mole of zinc sulfate and 1 mole of hydrogen.
Since sulfuric acid is in excess so Zinc is the limiting reagent
(Limiting reagent : Substance which get consumed when the reaction completes, limiting reagent helps in predicting the amount of products formed)
Limiting reagent (Zn) will decide the amount of Hydrogen produced
![Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)](https://tex.z-dn.net/?f=Zn%28s%29%20%2B%20H_%7B2%7DSO_%7B4%7D%28aq%29%20%5Crightarrow%20ZnSO_%7B4%7D%28aq%29%20%2B%20H_%7B2%7D%28g%29)
![1\ mole\ zinc\rightarrow 1\ mole\ H_{2}](https://tex.z-dn.net/?f=1%5C%20mole%5C%20zinc%5Crightarrow%201%5C%20mole%5C%20H_%7B2%7D)
So,
![5\ mole\ zinc\rightarrow 5\ mole\ H_{2}](https://tex.z-dn.net/?f=5%5C%20mole%5C%20zinc%5Crightarrow%205%5C%20mole%5C%20H_%7B2%7D)
Hence moles of Hydrogen produced is 5 moles
Uh no I can’t help but, I hope you have a good day!