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soldi70 [24.7K]
3 years ago
11

6. The illustration below represents the Grand Canyon..

Chemistry
1 answer:
andrew-mc [135]3 years ago
5 0
Hmm, I am not quite sure but if I am probably your best bet so I'd go with, either B or D.
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What's a third reaction? (Chemistry)
OLga [1]

Explanation:

a chemical reaction in which the rate of reaction is proportional to the concentration of each of three reacting molecules

3 0
3 years ago
Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about 39 kJ/g.
AnnZ [28]

Answer:

m=107.8g

Explanation:

Hello,

In this case, for the given information, we can compute the gained grams by firstly compute the energy consumed by 14.3 h of being sit relaxed and 9.70 h  of sleeping:

E_{sit}=120\frac{J}{s}*\frac{3600s}{1h}  *14.3h*\frac{1kJ}{1000J} =6177.6kJ\\\\E_{sleep}=83\frac{J}{s}*\frac{3600s}{1h}  *9.70h*\frac{1kJ}{1000J} =2898.36kJ

Then, we compute the energy used that day:

E_T=10000kJ-2898.36kJ-6177.6kJ=4203.28kJ

Finally, the mass by considering the consumed fat:

m=\frac{4203.28kJ}{39kJ/g} \\\\m=107.8g

Regards.

4 0
3 years ago
A block of aluminium occupies a volume of 11.1 mL and weighs 43 g. What is it's density? Give answer with one decimal.
horrorfan [7]

Answer:

<h2>Density = 3.9 g/ mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 43 g

volume = 11.1 mL

Substitute the values into the above formula and solve for the density

That's

Density =  \frac{43}{11.1}  \\  = 3.873873...

We have the final answer as

Density = 3.9 g/ mL to one decimal place

Hope this helps you

8 0
4 years ago
QUESTION 1: Using the experimental data, calculate the standard reduction potential for each metal, and organise them into a sta
suter [353]

Answer:you should search on google

Explanation:

because its useful

6 0
3 years ago
New cells are created from A) matter. B) energy. C) other cells. D) non-living matter.
Leokris [45]
Basically other cells
3 0
3 years ago
Read 2 more answers
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