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Dovator [93]
4 years ago
8

Which isotope of sulfur is the most naturally abundant

Chemistry
2 answers:
mamaluj [8]4 years ago
7 0

Answer:

MODE

Explanation:

Inessa [10]4 years ago
7 0

Answer:

The Isotope of sulfur.  

32S 94.99% stable.

33S 0.75%   Stable.

Explanation:

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The equation of state corresponding to 8 gm of Oxygen (O2) is : PV=RT,RT/4,RT/3 or RT/2?
nexus9112 [7]
In PV = nRT, n is the number of moles. When 8 grams of oxygen are present,
n = 8/32 = 1/4
So PV = RT/4
8 0
4 years ago
Read 2 more answers
What are three examples of organic matter in soil
Alborosie

Answer:

Bacteria, fungi and nematodes

5 0
3 years ago
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the atomic number of barium is 56. What do you know about the subatomic particles in an atom of this element ?
Deffense [45]
You definitely know that is has 56 protons and 56 electrons because atomic number is proton number and protons=electrons
7 0
4 years ago
If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.
kicyunya [14]
Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

CH_{3}COOH \ \textless \ ---\ \textgreater \   H^{+} + CH_{3}COO^{-}

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> [H^{+}]  = 10^{-2.88} =  0.001 moldm^{-3}

The change in Concentration Δ [CH_{3}COOH]= 0.001 moldm^{-3}


                                  CH3COOH          H+           CH3COOH    
Initial  moldm^{-3}                      x           0                     0
                                                                                                                       
Change moldm^{-3}        -0.001            +0.001           +0.001
                                                                                                       
Equilibrium moldm^{-3}      x- 0.001      0.001             0.001
                                                                              

Since the k_{a} value is so small, the assumption 
[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium} can be made.

k_{a} = [tex]= 1.8*10^{-5}  =  \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} =  \frac{0.001^{2}}{x}

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

         2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps! 



8 0
3 years ago
Examples 36
brilliants [131]

2x = 350- x

3x = 350

x = 350/x

therefore,

x = 116.67cm.

so, (350 - x)cm³ = (350- 166.67)cm³ = 233.33cm³

Hence distance covered by gas A is 116.67cm that by B is 233.33cm

5 0
4 years ago
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