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kondaur [170]
1 year ago
14

Calculate the molality and van’t Hoff factor (i) for the following aqueous solutions:

Chemistry
1 answer:
MissTica1 year ago
3 0

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<h3>What is the value of Van t Hoff factor?</h3>

For most non-electrolytes dissolved in water, the Van 't Hoff factor is essentially $ 1 $ . For most ionic compounds dissolved in water, the Van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

<h3>Which has highest Van t Hoff factor?</h3>

The Van't Hoff factor will be highest for

   A. Sodium chloride.

   B. Magnesium chloride.

   C. Sodium phosphate.

   D. Urea.

Learn more about van't off factor here:

<h3>brainly.com/question/22047232</h3><h3 /><h3>#SPJ4</h3>

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What mass of solid CaSO4 would need to be added in order to make 1.2L of a 0.75M solution?
liberstina [14]

Answer:

120

Explanation:

4 0
2 years ago
Na+CL2=2NACL is the balanced reaction for the formation of table salt. Given 20 grams of Na and 10 grams of Cl2, which reactant
Elina [12.6K]

Excess reactant : Na

NaCl produced : = 16.497 g

<h3>Further explanation</h3>

Given

Reaction(balanced)

2Na + Cl₂⇒ 2NaCl

20 g Na

10 g Cl₂

Required

Excess reactant

NaCl produced

Solution

mol Na(Ar = 23 g/mol) :

= 20 : 23 = 0.87

mol Cl₂(MW=71 g/mol):

= 10 : 71 g/mol = 0.141

mol : coefficient :

Na = 0.87 : 2 = 0.435

Cl₂ = 0.141 : 1 = 0.141

Limiting reactant : Cl₂(smaller ratio)

Excess reactant : Na

Mol NaCl based on mol Cl₂, so mol NaCl :

= 2/1 x mol Cl₂

= 2/1 x 0.141

= 0.282

Mass NaCl :

= 0.282 x 58.5 g/mol

= 16.497 g

4 0
2 years ago
How many total electrons can enter the set of 3p orbitals?<br> a. 3<br> b. 10<br> c. 2<br> d. 6
Sliva [168]

Answer:

For n=3 and l=1=p

It is 3p-orbital.

Magnetic quantum number m

l

have values from -l to +l and total of 2l+1 values.

Forl=1, m

l

values are:

m

l

=−1,0,1 for l=1; total m

l

values =3= Number of orbitals

Each orbital can occupy maximum of two electron

Number of electrons =2×3=6

Thus 6 electrons will show same quantum number values of n=3 and l=1.

Number of elements with last electron in 3p orbitals = 6

5 0
3 years ago
The fact that HBO2, a reactive compound, was produced rather than the relatively inert B2O3 was a factor in the discontinuation
Reil [10]

Answer:

1027.62 g

Explanation:

For B_2H_6  :-

Mass of B_2H_6  = 296.1 g

Molar mass of B_2H_6  = 27.66 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{296.1\ g}{27.66\ g/mol}

Moles\ of\ B_2H_6= 10.705\ mol

From the balanced reaction:-

B_2H_6(g) + 3 O2_{(l)}\rightarrow 2 HBO_2_{(g)}+ 2 H_2O_{(l)}

1 mole of B_2H_6 react with 3 moles of oxygen

Thus,

10.705 mole of B_2H_6 react with 3*10.705 moles of oxygen

Moles of oxygen = 32.115 moles

Molar mass of oxygen gas = 31.998 g/mol

<u>Mass = Moles * Molar mass = 32.115 * 31.998 g = 1027.62 g</u>

8 0
3 years ago
Please help its difficult
Likurg_2 [28]

Answer:

pounds

pounds pounds pounds

8 0
2 years ago
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