Explanation:
a. Adding a catalyst
no effect
.( Catalyst can only change the activation energy but not the free energy).
b. increasing [C] and [D]
Increase the free energy
.
c. Coupling with ATP hydrolysis
decrease the free energy value
.
d.Increasing [A] and [B]
decrease the free energy.
Answer:
Cp = 0.237 J.g⁻¹.°C⁻¹
Explanation:
Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 640 J
m = mass = 125 g
Cp = Specific Heat Capacity = <u>??</u>
ΔT = Change in Temperature = 43.6 °C - 22 °C = 21.6 °C
Solving eq. 1 for Cp,
Cp = Q / m ΔT
Putting values,
Cp = 640 J / (125 g × 21.6 °C)
Cp = 0.237 J.g⁻¹.°C⁻¹
I think it’s b hope that helped
Answer:
The required ratio would be 2:1