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OLga [1]
3 years ago
9

Describe and explain how electrical conductivity occurs in mercury bromide and mercury, in both solid and molten states.

Chemistry
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

HgBr2 conducts when molten because there are mobile ions in molten HgBr which allows flow of current when an electrical potential difference is introduced to the HgBr in molten state

However  HgBr2 does not conduct in the solid state as the ions are fixed in the solid HgBr2 lattice structure

Mercury, which is a metal in its natural form conducts both in the solid and molten states as the delocalized electrons are able to move both in the solid and molten mercury states and as such current flows through mercury when there is an electrical potential difference placed across it

Explanation:

Electricity or electric current flow is the term used to describe the state of movement or flow of matter that carries an electrical charge

It is the steady movement of or flow of electrons. The moving electrons transfer electrical charge round an electrical circuit. In metals, there are freely shared electrons between individual atoms so as to efficiently conduct electricity and so when an electrical potential difference is placed across a piece of  metallic object an electron is readily displaced by another electron entering from one end and exiting from the other end of the electrical potential difference

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If the temperature of 15 grams of water changes from 21C to 24C, how many joules of heat were involved? Show work
goblinko [34]

Answer:

189 Joules

Explanation:

Applying,

Q = cm(t₂-t₁)............. equation 1

Where Q = Heat, c = specific heat capacity of water, m = mass of water, t₁ = Initial Temperature, t₂ = Final temperature.

From the question,

Given: m = 15 grams = 0.015 kg, t₁ = 21 °C, t₂ = 24 °C

Constant: c = 4200J/kg.°C

Substitute these values into equation 1

Q = 0.015×4200×(24-21)

Q = 0.015×4200×3

Q = 189 Joules

6 0
2 years ago
Which is a net ionic equation for the neutralization of a weak acid with a strong base? which is a net ionic equation for the ne
Mkey [24]
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7 0
2 years ago
Which term names the group of organisms able to interbreed and produce fertile offspring?
vladimir2022 [97]

Answer:

Species

Explanation:

Species is the group of organisms able to interbreed and produce fertile offspring.

Let's break down each word in the question:

"Organisms" means living thing. It can be a plant or animal like we usually think of, but it also includes the really small single-celled living things like some bacteria.

"Interbreed" means to mate with each other.

"Fertile" means that the living thing can also have babies.

"Offspring" means the children that are born.

"Fertile offspring" means that the children that are made must be able to have babies of their own. For example, if a frog and a bird could interbreed, they might produce offspring (children). But, if those frog-birds cannot also have children, then frog-bird is not a species.

7 0
3 years ago
Since the half-life of 235U (7. 13 x 108 years) is less than that of 238U (4.51 x 109 years), the isotopic abundance of 235U has
Ymorist [56]

Answer:

\mathtt{ t_1-t_2= In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2} \ years}

Explanation:

Given that:

The Half-life of ^{235}U = 7.13 \times 10^8 \ years is less than that of ^{238} U = 4.51 \times 10^9 \ years

Although we are not given any value about the present weight of ^{235}U.

So, consider the present weight in the percentage of ^{235}U to be  y%

Then, the time elapsed to get the present weight of ^{235}U = t_1

Therefore;

N_1 = N_o e^{-\lambda \ t_1}

here;

N_1 = Number of radioactive atoms relating to the weight of y of ^{235}U

Thus:

In( \dfrac{N_1}{N_o}) = - \lambda t_1

In( \dfrac{N_o}{N_1}) =  \lambda t_1 --- (1)

However, Suppose the time elapsed from the initial stage to arrive at the weight of the percentage of ^{235}U to be = t_2

Then:

In( \dfrac{N_o}{N_2}) =  \lambda t_2  ---- (2)

here;

N_2 =  Number of radioactive atoms of ^{235}U relating to 3.0 a/o weight

Now, equating  equation (1) and (2) together, we have:

In( \dfrac{N_o}{N_1}) -In( \dfrac{N_o}{N_2}) =  \lambda( t_1-t_2)

replacing the half-life of ^{235}U = 7.13 \times 10^8 \ years

In( \dfrac{N_2}{N_1})  = \dfrac{In 2}{7.13 \times 10^9}( t_1-t_2)      ( since \lambda = \dfrac{In 2}{t_{1/2}} )

∴

\mathtt{In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2}= t_1-t_2}

The time elapsed signifies how long the isotopic abundance of 235U equal to 3.0 a/o

Thus, The time elapsed is  \mathtt{ t_1-t_2= In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2} \ years}

8 0
3 years ago
In an ideal situation where no heat energy is produced, what is the relationship between the chemical energy provided by the bat
kow [346]

Answer:

See explanation

Explanation:

The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another. Hence, chemical energy in a battery can be converted to electrical energy.

Usually, the conversion of energy from one form to another is not 100% efficient according to the second law of thermodynamics. Some energy is wasted in the process, sometimes as heat.

Hence, in an ideal situation where no heat energy is produced; all the chemical energy is converted to electrical energy (100% energy conversion). There will be no energy loss if no heat is produced.

6 0
2 years ago
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