In the ones place
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5x + 6 = 1
Subtract 6 from both sides.
5x = -5
Divide from both sides.
x = -1 (ANSWER)
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These are the two equation
10-2
13-5
Answer:
80 tickets
Step-by-step explanation:
Given the profit, y, modeled by the equation, y = x^2 – 40x – 3,200, where x is the number of tickets sold, we are to find the total number of tickets, x, that need to be sold for the drama club to break even. To do that we will simply substitute y = 0 into the given the equation and calculate the value of x;
y = x^2 – 40x – 3,200,
0 = x^2 – 40x – 3,200,
x^2 – 40x – 3,200 = 0
x^2 – 80x + 40x – 3,200 = 0
x(x-80)+40(x-80) = 0
(x+40)(x-80) = 0
x = -40 and x = 80
x cannot be negative
Hence the total number of tickets, x, that need to be sold for the drama club to break even is 80 tickets
Step-by-step explanation:
We have:
x - y = 43 , xy = 15
To find, the value of x^2+y^2x
2
+y
2
= ?
∴ x - y = 43
Squaring both sides, we get
(x - y)^2(x−y)
2
= 43^243
2
⇒ x^2+y^2x
2
+y
2
- 2xy = 1849
Using the algebraic identity,
(a - b)^2(a−b)
2
= a^2+b^2a
2
+b
2
- 2ab
⇒ x^2+y^2x
2
+y
2
= 1849 + 2xy
Put xy = 15, we get
x^2+y^2x
2
+y
2
= 1849 + 2(15)
⇒ x^2+y^2x
2
+y
2
= 1849 + 30
⇒ x^2+y^2x
2
+y
2
= 1879
∴ x^2+y^2x
2
+y
2
= 1879
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