Question

An animal park has lions, tigers and zebras. 20% of the animals are lions and half of the animals are zebras. If there are 120 animals at the park, how many tigers are there

Answer 1

Answer:

$36\ tigers$

Step-by-step explanation:

Let

x ----> the number of lions

y ----> the number f tigers

z ----> the number of zebras

we know that

$x+y+z=120$ ----> equation A

Remember that

$20\%=20/100=0.20$

$50\%=50/100=0.50$

To find out the number of lions, multiply the total animals by the percentage of lions

$x=0.20(120)=24\ lions$

To find out the number of zebras, multiply the total animals by the percentage of zebras

$z=0.50(120)=60\ zebras$

Substitute the value of x and the value of z in equation A and solve for y

$24+y+60=120$

$y+84=120$

$y=36\ tigers$