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stepladder [879]

3 years ago

13

Help please!!,,,,,,,,

1 answer:

ipn [44]3 years ago

6 0

Answer:

Question #3: Answer = 31

Step-by-step explanation

• Plug in 3 for x

• Plug in -4 for y

| -3(3)² + 2(-4) | -(3)(-4)

From here, simplify. Don't forget to use PEMDAS!

| -27 +8 | + 12

| -19 | + 12

19 + 12

31

Use this same method to solve for Question #2!

You might be interested in

What is the greatest common factor for 20,and 45x

nadya68 [22]

<span>20: 1,2,4,5,10,20
45: 1,3,5, 9, 15,45
so five is the greatest common factor of 20 and 45x</span>

4 0

4 years ago

Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the gi

kompoz [17]

Answer:

The general solution is

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2}$

Step-by-step explanation:

Step :1:-

Given differential equation y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

$(D^4 -2D^3+D^2)y = e^x+1$

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

$m^4 -2m^3+m^2 = 0$

$m^2(m^2 -2m+1) = 0$

$(m^2 -2m+1) this is the expansion of (a-b)^2$

$m^2 =0 and (m-1)^2 =0$

The roots are m=0,0 and m =1,1

complementary function is $y_{c} = (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x$

<u>Step 2</u>:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x + \frac{1}{D^{2} } e^{0x}$

$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

$I_{2}$ $= \frac{1}{D^2(D-1)^2}e^{0x}$

$\frac{1}{D} \int\limits {1} \, dx= \frac{1}{D} x$

again integration $\frac{1}{D} x = \frac{x^2}{2!}$

The general solution is $y = y_{C} +y_{P}$

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2!}$

3 0

3 years ago

Need help & Thank you !!!!

loris [4]

The right answer is of option D.

please see the attached picture for full solution...

Hope it helps...

Good luck on your assignment......

8 0

3 years ago

85 of 40 emails I need more help is very stugle

Lady bird [3.3K]

40÷85 =÷ 0.47058823529

3 0

3 years ago

Kevin, Michael and Darren all do their own laundry at home. Kevin does his laundry every 9 days, Michael every 10 days, and Darr

VladimirAG [237]

Answer:

In 180 days the three of them will do their laundry again on the same day.

Step-by-step explanation:

we need to find the least common factor or 9, 10 and 12:

LCM(9, 10, 12) = 180

5 0

3 years ago

Read 2 more answers