Question

an angle exceeds three times its complement by 10 find it. please explain properly i will mark as brilliant ​

Answer 1

Answer:

one angle is 20° and the other is 70°

Step-by-step explanation:

Complementary angles add up to 90°.

Here it is given that an angle exceeds 3 times its complement by 10. So, we are taking the complement as x. Since it exceeds its complement 3 times, we are multiplying the complement 3 times. so we get $3x$.

Now we also need to add 10, so we get the final equation $3x+10$, which is the second angle.

As of now, first angle = x and second angle =  3x+10.

Since they are complementary angles, both angles add up to 90°

⇒ 1st angle + 2nd angle = 90°

∴ $x+3x+10 = 90$  [since 3x and x are like expressions, we should add 3x + x = 4x]

⇒ $4x = 90 - 10$  [by transposing 10 from LHS to RHS]

⇒ $4x = 80$

⇒ $x = \frac{80}{4}$  [by transposing 4 from LHS to RHS]

⇒ $x = 20$

∴The complementary angle is 20° and the given angle is [(3 × 20) + 10)] = 70°

Answer 2

Answer:

It's supplementary angle I think