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scoundrel [369]
2 years ago
8

Pick two angles one in degrees and one in radians in two different quadrants. State the angle and the quadrant in which the term

inal side lies
Mathematics
1 answer:
mestny [16]2 years ago
6 0

The two angles to be selected are as follows with their termination quadrants respectively;

  • 130° = The terminal side of the angle lies in the second quadrant.
  • (4π/3) radians= The terminal side of the angle lies in the third quadrant.

<h3>What is the terminal side of the angles selected?</h3>

According to the task content, two angles are to be selected in which case one is in degrees and the other in radians with the quadrants in which their terminal sides lie.

Consequently, it follows from convention that the angles in discuss are as follows;

  • 130° = The terminal side of the angle lies in the second quadrant.

  • (4π/3) radians= The terminal side of the angle lies in the third quadrant.

Ultimately, the angles are as represented above in which case, (4π/3) radians is equivalent to 240°.

Read more on terminal side of angles;

brainly.com/question/16649403

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ohaa [14]
A. (2,6)(5,0)
     slope = (0 - 6) / (5 - 2) = -6/3 = -2

y = mx + b
slope(m) = -2
(2,6)..x = 2 and y = 6
sub and find b, the y int
6 = -2(2) + b
6 = -4 + b
6 + 4 = b
10 = b

so line A , equation is : y = -2x + 10
============================
B. (0,2)(6,6)
    slope = (6 - 2) / (6 - 0) = 4/6 which reduces to 2/3

y = mx + b
slope(m) = 2/3
(0,2)...x = 0 and y = 2
sub and find b, the y int
2 = 2/3(0) + b
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LIne B, equation is : y = 2/3x + 2
=========================
so we have : 
y = 2/3x + 2
y = -2x + 10

2/3x + 2 = -2x + 10 ..multiply by 3
2x + 6 = -6x + 30
2x + 6x = 30 - 6
8x = 24
x = 24/8
x = 3

y = -2x + 10
y = -2(3) + 10
y = -6 + 10
y = 4

solution is (3,4).....3/4 is the solution to both lines <===

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Copy Cat Copies charges 18 cents for the first copy and 12 cents for each additional copy. What is the greatest number of copies
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12x23= 276 which is $2.76
then you add 276+18= 294

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4 years ago
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What is the maximum value of P = 24x + 30y, given the constraints on x and y listed below? 120 132 138 150
Marina CMI [18]

Answer:

So the maximum value of P is 138.

Step-by-step explanation:

P(0,0)= 24(0) + 30(0)  =0

P(0,1)= 24(0) + 30(1)  =30

P(5,0)= 24(5) + 30(0)  =120

P(2,3) =24(2) + 30(3)  = 138

I also attached the graph images and constraints image as well so according to this is answer for this question, and i hope you got the idea thanks.

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16 is the answer. All 3 numbers can be divided by 16 at most. It can’t be 16a because 48b does not have a. It can’t be 16b because 32a does not have b.
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