Answer:
Area of circle R = 75π un² or ≈235.5 un²
Step-by-step explanation:
The problem says that m∠TRS = 120º. The total number of degrees in a circle is 360º. 120º is a third of 360º. Therefore, we can prove that the shaded sector is a third of the circle.
The problem then says that the area of the shaded sector is 25π and we have to calculate the area of the entire circle. Since we already know that the shaded sector is a third of the circle, we can simply multiply 25π by 3 in order to calculate the area of t he entire circle.
25π × 3 = 75π.
Area of circle R = 75π un² or ≈235.5 un²
Answer:
Then the total area is 116 cm^2 which agrees with answer D
Step-by-step explanation:
Notice we need to calculate the area of two rectangles (one larger at the bottom and a smaller one on top)
The Area of a rectangle is the product: base x height
In our case :
Area of Big rectangle = 12 cm x 7 cm = 84 cm^2
Area of smaller rectangle = 8 cm x 4 cm = 32 cm^2
Then the total area is: 84 cm^2 + 32 cm^2 = 116 cm^2
Answer:
Equation of the line that passes through the point (-2,7) and has a slope of zero is given as
Step-by-step explanation:
Equation of line is given as
-----------(1)
Here
Substituting values in equation (1)
Answer: E: The number of books a person finished reading last month
Step-by-step explanation:
First, a discrete variable is a variable that only can take some given values in a set, the discrete variables are usually not dense, and a continuous variable is a variable that can take any value in a range (where the accepted values are dense).
So, for example, the set of the natural numbers is discrete, and the set of the real numbers can represent a continuous variable.
Here the only option that is really discrete will be the number of books that a person finished reading last month because here only positive whole numbers are accepted (you can not finish a 0.454 of a book)
The other options are continuous because all are classical measures.
For example, the weight of a person can jump between:
75.6kg and 75.7kg.
So you could think that this is discrete because the values between 75.6kg and 75.7g are not shown with our measuring device, but those will be added in the error of the measure because the weights between 75.6kg and 75.7kg are actually possible, so they must be accepted.
the answer is c
the y-intercept is 10–it doesn’t have a negative sign, so it is positive
