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nevsk [136]
3 years ago
8

Data will be collected on the following variables. Which variable can be considered discrete? A. The height of a person B . The

weight of a person C. The length of a person’s arm span D The time it takes for a person to solve a puzzle E The number of books a person finished reading last month
Mathematics
1 answer:
kvv77 [185]3 years ago
4 0

Answer: E: The number of books a person finished reading last month

Step-by-step explanation:

First, a discrete variable is a variable that only can take some given values in a set, the discrete variables are usually not dense, and a continuous variable is a variable that can take any value in a range (where the accepted values are dense).

So, for example, the set of the natural numbers is discrete, and the set of the real numbers can represent a continuous variable.

Here the only option that is really discrete will be the number of books that a person finished reading last month because here only positive whole numbers are accepted (you can not finish a 0.454 of a book)

The other options are continuous because all are classical measures.

For example, the weight of a person can jump between:

75.6kg and 75.7kg.

So you could think that this is discrete because the values between 75.6kg and 75.7g are not shown with our measuring device, but those will be added in the error of the measure because the weights between 75.6kg and 75.7kg are actually possible, so they must be accepted.

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If 26.97 ÷ 6.3 is written in long division form as so that the divisor is written as a whole number, where should the decimal po
Soloha48 [4]
<h2>Answer:</h2>

The decimal point should be placed between digits 9 and 7 in the dividend. i.e the dividend becomes 269.7

<h2>Step-by-step explanation:</h2>

Dividend = 26.97       [numerator]

Divisor = 6.3               [denominator]

If 26.97 ÷ 6.3 is written in long division form so that the divisor is written as a whole number, we have the following;

(i)First convert the divisor to a whole number by multiplying by 10 i.e

6.3 x 10 = 63

(ii) Since the divisor (denominator) has been multiplied by 10, to make sure the division expression stays the same, we need to multiply the dividend(numerator) too by 10. i.e

26.97 x 10 = 269.7

(iii) The division expression then becomes;

269.7 ÷ 63

Therefore, the decimal point should be placed between digits 9 and 7 in the dividend.

8 0
3 years ago
3080.34 rounded to the nearest whole number
Allushta [10]

Answer:

3080

Step-by-step explanation:

this is because after the decimal there is a 3 and when you round with a 3 the number stays the same.

4 0
3 years ago
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Help me out with this please
kakasveta [241]

Answer:

i think it is a but not shour

Step-by-step explanation:

7 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
4 years ago
I need help with this geometry question.
sashaice [31]

Answer:

Step-by-step explanation:

a). There are 8 points in the figure attached.

b). There are 9 lines in the given figure.

c). There are 5 planes in the figure attached.

d). Three collinear points are D,G and F.

e).  Four co-planar points are G, F, H and C.

f). Intersection of planes ABC and ABE is the common line AB.

g). Intersection of planes BCH and DEF is the common line EF.

h). Intersection of AD and DF is a point D.

3 0
3 years ago
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