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3 years ago

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The band sold 385 cases of fruit. There are 24 bags of fruit in each case. Which is the best estimate of the number of bags of f

ruit sold?
A. 900 bags of fruit
B. 1,000 bags of fruit
C. 6,000 bags of fruit
D. 10,000 bags of fruit

1 answer:

fredd [130]3 years ago

8 0

D, 385 times 24 equals 9,240

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Anything raised to exponent 0 equals 1

So

$x^{0}=1$

So we get

$\frac{9 (1) y^8}{z^8} = \frac{9y^8}{z^8}$

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Each unit on a coordinate plane represents 1 mile. One end of the road starts at (212,23). The road ends at (6,23). How long is

olya-2409 [2.1K]

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3 years ago

In the diagram below, DE is parallel to XY. What is the value of y?

nasty-shy [4]

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94

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Colin gets pic 'n mix when at the cinema and makes his bag up with 3 types of sweet. He pick:

Kisachek [45]

Answer: 2/3

Explanation: Assume that the number of smarties he picked is c.

Now, we are given that:

1- He picked 3 times as many cola bottles as smarties. This means that:

Number of cola bottles he picked = 3s

2- He picked twice as many smarties as marshmallows. This means that:

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Now to get the proportion o f cola bottles, we will divide the number of cola bottles by the total number of sweets as follows:

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Hope this helps :)

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2 years ago

Three spherical balls with radius r are contained in a rectangular box. two of the balls are each touching 5 sides of the rectan

olganol [36]

Answer:

The volume of the space between the balls and the rectangular box is $4r^{3}(6 - \pi)$

Step-by-step explanation:

The attachment below shows the description of the rectangular bow and the three spherical balls.

From the description,

Two of the balls are each touching 5 sides of the rectangular box, say the 5 sides touched by one of the balls are sides 1,2,3,4, and 5; then the other ball will touch sides 2,3,4,5, and 6).
The middle ball also touches four sides of the rectangular box, These four sides touched by the middle ball will be sides 2,3,4, and 5.

This means the balls are tightly fitted into the rectangular box.

Each of the balls has a radius r

Hence, The volume of one of the balls is given by the volume of a sphere

$Volume of a sphere = \frac{4}{3} \pi r^{3} \\$

The volume occupied by one of the balls is $\frac{4}{3} \pi r^{3} \\$

∴ The volume occupied by the three spherical balls will be

3 × $\frac{4}{3} \pi r^{3} \\$

= $4\pi r^{3}$

The volume occupied by the three spherical balls $4\pi r^{3}$

For the rectangular box,

The volume of a rectangular box = $l w h$

Where $l\\$ is the length

$w$ is the width and

$h$ is the height

Since the balls are tightly packed,

The width of the rectangular box will be the diameter of the balls

diameter of the balls = 2r

∴ $w$ = 2r

The height of the rectangular box will also be the diameter of the balls

∴ $h$ = 2r

The length of the rectangular box will be 3 times the diameter of the balls

∴ $l$ = 3 × 2r = 6r

Hence,

The volume of a rectangular box = 6r × 2r × 2r

= 24r³

The volume of the space between the balls and the rectangular box is given by

Volume of the space between the balls and the rectangular box =

volume of the rectangular box - volume occupied by the three spherical balls

Volume of the space between the balls and the rectangular box= 24r³ - 4πr³

= 24r³ - 4πr³

= 4r³(6 - π)

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3 years ago