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2 years ago

A flagpole is 48 feet tall.

Mathematics

1 answer:

Vadim26 [7]2 years ago

4 0

Root 50^2 - 48^2 = 14ft

The distance of the base is 14ft

Hope this helps!

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Write the equation in y-intercept form slope 2 passes through point (5,-2)

Alenkinab [10]

<h2>Answer</h2>

The equation is y = 2x - 12

<h2>Explanation</h2>

Equation in slope intercept form is

$y = mx + b$

Where,

m = slope

b = y-intercept

Putting the value of slope in this equation:

$y = 2x + b$

From this we can solve the equation for b

$b = y - 2x$

$b = -2 - 2(5)$

$b = -12$

Now, the equation of y-intercept becomes

$y = 2x - 12$

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3 years ago

Hello please help i’ll give brainliest

xenn [34]

Answer:

before "however"

Step-by-step explanation:

However is a throw-in word and should be both preceded and superseded by a comma.

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3 years ago

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Which number makes this sentence true? 7.8×3.6×1=7.8×? 1,3.6,4.6,7.8

marin [14]

In the left hand side, you're multiplying 7.8 by $3.6\times 1$

In the right hand side, you're multiplying again 7.8 by a mysterious number.

So, the unknown number must be $3.6\times 1$

Every number remains unchanged when multiplied by 1, so the answer is 3.6

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3 years ago

A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

pav-90 [236]

Answer:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

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2 years ago

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nexus9112 [7]

Answer:

x=4

Step-by-step explanation:

56/14=4

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3 years ago

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