Answer:
Step-by-step explanation:
If the bricklayer can construct the wall in its entirety in 3 hours, then he can get 1/3 of the job done in an hour.
If the apprentice can get the whole job done in 5 hours, then he can get 1/5 of the job done in an hour. If they both work together on said job, the equation is
and now we solve for x. Multiply everything by the LCM to get rid of the fractions. That would be 15x:
and doing that gives us
5x + 3x = 15 and
8x = 15 so
x = 1.875 hours which is 1 7/8 hours which is also 1 hour and 52 1/2 minutes.
A jar of jelly beans contains 50 red gumballs , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly
select a jelly bean, then select another without
putting the first jelly bean back. What is the
probability that you draw two red jelly beans? This is Dependent because you didnt put the other jelly bean in thus changing the total nmber of jelly beans.
A jar of jelly beans contains 50 red gumballs<span> , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly select a jelly bean, then select another while replacing the first jelly bean back. What is the probability that you draw two red jelly beans? This is Independent because you put the other jelly bean in thus keeping the total number of jelly beans.</span>
Answer:
(a) 12.96 ft²
(b) 21.5 in²
Step-by-step explanation:
(a) For the first diagram
Area of the shaded region (A) = Area of Tripezium- area of circle
A = [1/2(a+b)h]-[πr²]............... Equation 1
Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.
From the diagram,
Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.
Constant: π = 3.14
Substitute these values into equation 1
A = [12(15+6)/2]-(3.14×6²)
A = 126-113.04
A = 12.96 ft²
(b) For the second diagram,
Area of the shaded region (A') = Area of square- area of circle
A' = (L²)-(πr²)............. Equation 2
Where L = lenght of one side of the square, r = radius of the circle
From the diagram,
Given: L = 2r = (2×5) = 10 in, r = 5 in
Substitute these values into equation 2
A' = (10²)-(3.14×5²)
A' = 100-78.5
A = 21.5 in²
