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user100 [1]
2 years ago
12

Slope of (4, -3) and (-1, 5)

Mathematics
1 answer:
Mumz [18]2 years ago
4 0

Answer: -\frac{8}{5}

Step-by-step explanation:

     Slope can be found with change in y over change in x.

           \displaystyle \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

           \displaystyle \frac{5--3}{-1-4}

           \displaystyle \frac{5+3}{-1-4}=\frac{8}{-5}

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Solve: -3b-(6b+12)=-9b+13
andre [41]

Answer:

they equal the same thing casue the second one is simplified

Step-by-step explanation:

4 0
3 years ago
Let f(x)=14/7+2e^−0.6x . What is f(3) ? Enter your answer, rounded to the nearest tenth, in the box.
Gelneren [198K]

Answer:

f(3)=1.9

Step-by-step explanation:

we have

f(x)=\frac{14}{7+2e^{-0.6x}}

we know that

f(3) is the value of the function for the value of x equal to 3

so

substitute the value of x=3 in the function

f(3)=\frac{14}{7+2e^{-0.6(3)}}=1.9

5 0
3 years ago
Question 4: The storage in a reach of a river at a point in time is 255 m3 (meters cubed) . Determine the average rate of inflow
irakobra [83]

Answer:

0.319 m³/s

Step-by-step explanation:

Data provided:

Initial volume in the river = 255 m³

Final volume required in the storage = 325 m³

Average outflow = 0.30 m³/s

Duration for raising the level = 1 hour = 3600 seconds

Now,

The actual volume required to raise the volume to 325 m³

= Final volume - Initial volume

= 325 m³ - 255 m³

= 70 m³

also,

the amount of outflow in 1 hour = Average rate of outflow × Time

= 0.30 m³/s × 3600 s

= 1080 m³

Therefore,

the total volume required = 1080 m³ + 70 m³ = 1150 m³

Now,

the average rate of inflow required = \frac{\textup{Total volume required}}{\textup{Time}}

= \frac{\textup{1150}}{\textup{3600}}

= 0.319 m³/s

8 0
4 years ago
The number of internet paid search ads is increasing as advertisers move away from traditional marketing methods. The equation y
blondinia [14]

Answer: In 2005 the amount spend on internet ads = $74.6 billions.

In 2009 spending on internet search ads will reach $102 billion .

Step-by-step explanation:

Given : The number of internet paid search ads is increasing as advertisers move away from traditional marketing methods.

The equation y=6.9x+40.1 can be used to project spending on internet search ads, in billions of dollars, x years after 2000.

To estimate spending on internet ads in 2005.

We need to put x= 5 in the above equation   [∵2005-2000=5]

y=6.9(5)+40.1

y=34.5+40.1

y=74.6

i.e. In 2005 the amount spend on internet ads = $74.6 billions.

Put y= 102 in the given equation, we get

102=6.9x+40.1

61.9=6.9x   [Subtract 40.1 from both sides]

x=\dfrac{61.9}{6.9}=\dfrac{619}{69}=8.97101449275\approx9

And 2000+9=2009 [x is the number of years after 2000]

Hence, in 2009 spending on internet search ads will reach $102 billion .

3 0
3 years ago
cos60=5/zy ??? how do I get rid of the 5? Normally I would multiply by the denominator but that doesn't work here. The end answe
saw5 [17]

cos 60 = 1/2

1/2 = 5/zy

1= 10/zy

zy=10

8 0
2 years ago
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