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lys-0071 [83]
2 years ago
11

39. Why are -2a and 18a like terms?

Mathematics
1 answer:
Vesnalui [34]2 years ago
7 0

Answer:

they each share the same variable which is raised to the same exponent, 1

Step-by-step explanation:

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If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?2
aivan3 [116]

The second equation because they all have a common factor of 3. You can get x by itself. However, with the first one, you'll end up with fractions instead.

8 0
3 years ago
The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original
evablogger [386]

<em>Here</em> as the <em>Pentagon</em> is <em>regular</em> so it's <em>all sides</em> will be of <em>equal length</em> . And if we assume It's each side be<em> </em><em><u>s</u></em> , then it's perimeter is going to be <em>(s+s+s+s+s) = </em><em><u>5s</u></em>.And as here , each <em>side</em> is increased by <em>8 inches</em> and then it's perimeter is <em>65 inches</em> , so we got that it's side after increament is<em> (s+8) inches</em> and original length is <em>s inches </em>. And if it's each side is <em>(s+8) inches</em> , so it's perimeter will be <em>5(s+8)</em> and as it's equal to <em>65 inches</em> . So , <em><u>5(s+8) = 65</u></em>

{:\implies \quad \sf 5(s+8)=65}

{:\implies \quad \sf 5s+5\times 8=65}

{:\implies \quad \sf 5s+40=65}

{:\implies \quad \sf 5s=65-40}

{:\implies \quad \sf 5s=25}

{:\implies \quad \sf s=\dfrac{25}{5}=5}

{:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}

As we assumed the original side to be <em><u>s</u></em> .

<em>Hence, the original side's length 5 inches </em>

8 0
2 years ago
Reuben is making a replica of the US flag for his school project.
Leno4ka [110]
P1=2.5+2.5+4.75+4.75=14.5 cm

0.5 cm - 1 in
2.5 cm - 5 in
4.75 cm - 9.5 in

P2=5+5+9.5+9.5=29 in
8 0
3 years ago
F(x) = 5x2 − 70x + 258. Complete the square.
astraxan [27]
5(x^2 - 14x + 258/5)
= 5((x-7)^2 -49+258/5)
= 5((x-7)^2 + 13/5)
= 5(x-7)^2 + 13
I belive this is how it should be done
7 0
3 years ago
Please help me with this question!!
ziro4ka [17]
Your answer would be A.) False; either both are right or one is obtuse

Two acute angles added could never equal 180

Hope this helps!
5 0
3 years ago
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