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SOVA2 [1]
1 year ago
14

The orbital shape, i.e. the radial probability distribution, of the 2s sublevel shows it to be more stable than that of the 2p s

ublevel because it penetrates closer to ______.
Chemistry
1 answer:
olga_2 [115]1 year ago
5 0

The orbital shape, i.e. the radial probability distribution, of the 2s sublevel shows it to be more stable than that of the 2p sublevel because it closer to The nucleus.

The nucleus of an atom consists of neutrons and protons, which in flip are the manifestation of more primary debris, known as quarks, which are held in affiliation through the nuclear sturdy pressure in positive solid combos of hadrons, referred to as baryons.

The nucleus of the atom, also called the atomic nucleus, is the small, dense, spherical center of an atom. The nucleus incorporates  subatomic debris: the protons and the neutrons. Protons are definitely charged particles with a mass of about 1 amu (atomic mass unit).

It is composed of protons, which have a fantastic charge, and neutrons, which haven't any price. Protons, neutrons, and the electrons surrounding them are lengthy-lived particles found in all ordinary, clearly going on atoms.

Learn more about orbital shape here:-brainly.com/question/28065771

#SPJ4

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6.25 moles of N₂ is produced, and 18.8 moles of Cu and H₂O is produced.

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We are given the chemical equation:

\displaystyle 2\text{NH$_3$}_\text{(g)} + 3\text{CuO}_\text{(s)} \longrightarrow \text{N$_2$}_\text{(g)}  + 3\text{Cu}_\text{(s)}+3\text{H$_2$O}_\text{(g)}

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Compute using stoichiometry. From the equation, we can see the following stoichiometric ratios:

  • The ratio between NH₃ and N₂ is 2:1. (i.e. One mole of N₂ is produced from every two moles of NH₃.)
  • The ratio between NH₃ and Cu is 2:3.
  • The ratio between NH₃ and H₂O is 2:3. (i.e. Three moles of H₂O or Cu is produced frome every two moles of NH₃.)

Dimensional Analysis:

  • The amount of N₂ produced:

\displaystyle 12.5\text{ mol NH$_3$} \cdot \frac{1\text{ mol N$_2$}}{2\text{ mol NH$_3$}} = 6.25\text{ mol N$_2$}

  • The amount of Cu produced:

\displaystyle 12.5\text{ mol NH$_3$} \cdot \frac{3\text{ mol Cu}}{2\text{ mol NH$_3$}} = 18.8\text{ mol Cu}

  • And the amount of H₂O produced:

\displaystyle 12.5\text{ mol NH$_3$} \cdot \frac{3\text{ mol H$_2$O}}{2\text{ mol NH$_3$}} = 18.8\text{ mol H$_2$O}

In conclusion, 6.25 moles of N₂ is produced, and 18.8 moles of Cu and H₂O is produced.

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