Benzene is the simplest example of _____ compound.

1 answer:

4 0

Benzene is the simplest example of the aromatic compound
Firstly, we want to explain what is the meaning of aromaticity?
the aromaticity is called on any compound which has cyclic shape and has a resonance. Resonance is delocalization of the electrons (which form the double bond) in the molecules, in other words, the double bond moves through the compound by the movement of electrons which leads to increasing the stability of the compound by this process which called resonance. The resonance may occur in open or cyclic compounds, and if it occurs in cyclic compounds, these compounds are called aromatic compounds. So, the benzene considered to be the simplest aromatic compound where it is not only has a resonance in a cyclic ring but also it was the first aromatic compound discovered and also, the most common aromatic compounds are derivatives of it (benzene).

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First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.

Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

=> number of moles = 12.62 g / 17 g/mol = 0.742 mol

Heat1 = #moles * heat capacity * ΔT

Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J

2) Vaporization

Heat2 = # moles * H vap

Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J

3) Vapor heating

Heat3 = #moles * heat capacity * ΔT

Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

Third, add up the heats for every steps:

Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J

Fourth, divide the total heat by the heat rate:

Time = 22,466.3 J / (6000.0 J/min) = 3.7 min

Answer: 3.7 min

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