The answer is 4.0 moles of magnesium
because...
..
...4.0mol Makmol O2 =3.0mol O2
8.43
58.44g/mol*1/6.93g= 8.43moles of NaCL
Answer:
You will have 19.9L of Cl2
Explanation:
We can solve this question using:
PV = nRT; V = nRT/P
<em>Where V is the volume of the gas</em>
<em>n the moles of Cl2</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is 273.15K assuming STP conditions</em>
<em>P is 1atm at STP</em>
The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:
63g * (1mol / 70.906g) = 0.8885 moles
Replacing:
V = 0.8885mol*0.082atmL/molK*273.15K/1atm
V = You will have 19.9L of Cl2
1. The resulting concentration will be 0.00044 mol/L
2. The minimum mass of sodium sulfite to add will be 0.4032 grams.
<h3>Stoichiometric problems</h3>
1. Using m1v1=m2v2
m1 = 0.01 mol/L, v1 = 20 mL, v2 = 450 mL
m2 = m1v1/v2 = 0.01 x 20/450 = 0.00044 mol/L
2. 
Mole ratio of the reactants = 1:1
Mole of 80 mL, 0.0400 mol/L Ca(NO3)2 = 80/1000 x 0.0400 = 0.0032 mol
Equivalent mole of Na2SO3 = 0.0032 moles
Mass of 0.0032 moles Na2SO3 = 0.0032 x 126 = 0.4032 grams
Thus, the minimum mass of sodium sulfite to be added must be 0.4032 grams.
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Answer:
C. The ability to release tremendous amounts of energy
Explanation:
The decay of massive and unstable nuclei which leads to the formation of newer atoms or nuclei accompanied by the release of energy is known as nuclear fission. In a splitting reaction such as fission, energy is released from the conversion of mass.
The energy released in a fission reaction can be used to generate electricity through a series of process. Most advanced countries in the world generates their electricity through this process.