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Yuliya22 [10]
3 years ago
8

Terry, a student, performs a titration. He completes these steps as part of his titration procedure: 1. He cleans and rinses a b

urette with standardized base. 2. He fills the burette with standardized base solution. 3. He reads and records the initial burette volume. 4. He adds a base from the burette to an acid. 5. He observes a color change in the Erlenmeyer flask. 6. He stops the addition of base from the burette. 7. He reads and records the final burette volume. Which steps will provide information needed to calculate the volume of base needed to reach the equivalence point? A. 1 and 6 B. 3 and 7 C. 3, 4, and 6 D. 1, 2, and 7
Chemistry
2 answers:
Contact [7]3 years ago
6 0

Answer:

D

Explanation:

D is the answer because 2 is needed to know

Masja [62]3 years ago
3 0

Answer:

B) 3 and 7

Explanation:

i just took the test

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JulsSmile [24]
The answer is 4.0 moles of magnesium
because...
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...4.0mol Makmol O2 =3.0mol O2
6 0
3 years ago
How many moles of NaCl are there in 6.93g?
kkurt [141]
8.43
58.44g/mol*1/6.93g= 8.43moles of NaCL
5 0
3 years ago
How many liters of Cl2 gas will you have if you are using 63 g of Na?
ELEN [110]

Answer:

You will have 19.9L of Cl2

Explanation:

We can solve this question using:

PV = nRT; V = nRT/P

<em>Where V is the volume of the gas</em>

<em>n the moles of Cl2</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is 273.15K assuming STP conditions</em>

<em>P is 1atm at STP</em>

The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:

63g * (1mol / 70.906g) = 0.8885 moles

Replacing:

V = 0.8885mol*0.082atmL/molK*273.15K/1atm

V = You will have 19.9L of Cl2

6 0
3 years ago
Please help me with this question
Leviafan [203]

1. The resulting concentration will be 0.00044 mol/L

2. The minimum mass of sodium sulfite to add will be 0.4032 grams.

<h3>Stoichiometric problems</h3>

1. Using m1v1=m2v2

  m1 = 0.01 mol/L, v1 = 20 mL, v2 = 450 mL

 

       m2 = m1v1/v2 = 0.01 x 20/450 = 0.00044 mol/L

2. Na_2SO_3 + Ca(NO_3)_2 --- > 2NaNO_3 + CaSO_3

Mole ratio of the reactants = 1:1

Mole of 80 mL, 0.0400 mol/L Ca(NO3)2 = 80/1000 x 0.0400 = 0.0032 mol

Equivalent mole of Na2SO3 = 0.0032 moles

Mass of 0.0032 moles Na2SO3 = 0.0032 x 126 = 0.4032 grams

Thus, the minimum mass of sodium sulfite to be added must be 0.4032 grams.

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

8 0
2 years ago
What is a beneficial aspect of nuclear fission?
LUCKY_DIMON [66]

Answer:

C. The ability to release tremendous amounts of energy

Explanation:

The decay of massive and unstable nuclei which leads to the formation of newer atoms or nuclei accompanied by the release of energy is known as nuclear fission. In a splitting reaction such as fission, energy is released from the conversion of mass.

The energy released in a fission reaction can be used to generate electricity through a series of process. Most advanced countries in the world generates their electricity through this process.

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