H2SO4 + Na2CO3 → Na2SO4 + CO2 + H2O
The molarity of sulfuric acid if 1.78 L were used in the above reaction is
0.453 M (answer 2)
Calculation
find the moles of water produced = mass/molar mass
= 14.5 g /18 g/mol = 0.806 moles
by use of of mole ratio between H2So4 to H2O which is 1:1 the moles of H2SO4 is also = 0.806 moles
Molarity of H2SO4 is therefore = moles/volume in liters
= 0.806 mol/ 1.78 L = 0.453 M (answer 2)
Answer:
Volume = 45.62L
Explanation:
Data;
V1 = 54.9L
T1 = 64°C = (64 + 273.15)k = 337.15K
T2 = 7°C = (7 + 273.15)k = 280.15K
V2 = ?
From Charles law,
The volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant
V = KT, K = V / T = V1 / T1 = V2 / T2 = V3 / T3 =.........= Vn / Tn
(54.9 / 337.15) = (V2 / 280.15)
V2 = (54.9 * 280.15) / 337.15
V2 = 45.618L
V2 = 45.62L
Whewww!! What class is this for
Kinda confused what worksheet your on
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