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denis-greek [22]
2 years ago
11

A sample of n2 occupies 3. 0l at 3. 0atm. What volume will it occupy when the pressure is changed to 0. 5atm and the temperature

remain constant?
Chemistry
1 answer:
belka [17]2 years ago
7 0

It will occupy 18 L volume when the pressure is changed to 0. 5 atm and the temperature remain constant.

Calculation,

According to Boyle law, the pressure of a given quantity of gas varies inversely with its volume at constant temperature.

P_{1} V _{1} = k    .....(i)

  • P_{1} is initial pressure = 3 atm
  • V _{1} is initial volume = 3L
  • k is constant

P_{2} V _{2} = k    (ii)

  • P_{2} is final pressure = ?
  • V _{2} is final volume = 0.5atm
  • k is constant

Combining equation (i) and (ii). we get,

P_{1} V _{1}  = P_{2} V _{2}

3 atm× 3L=  V _{2}× 0.5atm

V _{2}  =   3 atm× 3L/0.5atm = 18 L

Boyle law used during respiration or breathing.

To Learn more about Boyle law

brainly.com/question/1437490

#SPJ4

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Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem
belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound             Amount

  Fe₂O₃                     3.95 g

     H₂                        4.77 g

     Fe                        4.38 g

    H₂O                      2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M

  • <u>For water:</u>

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

For the given chemical equation:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

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2. Does the aluminum sample (the can) contain more than, (less than or exactly one mole of aluminum? Support answer with calcula
mrs_skeptik [129]

Answer:

than, (less than or exactly one mole

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